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4 years ago

What is (-3+2i)(-6-8i)

Mathematics

1 answer:

Nataliya [291]4 years ago

6 0

Do foil
First, outside, inside last

18 +24i - 12i + 16
(two i = -1)

18 - 12i + 16 is your answer

hope this helps

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Marco has a bag of 50 colored marbles.there are 12 blue marbles,18 black marbles,and 20 red marbles.what is the ratio of the num

iren2701 [21]

The answer is 2:3 because it is 12:18 simplified.

8 0

3 years ago

Solving systems of equations by substitution<br> Y=6x y=5x+7

soldi70 [24.7K]

Y=6x (1)
y=5x-7 (2)

Substitute y into (2)
(6x)=5x-7 -- subtract 5x from both sides
x=-7

Sub x into 1
y=6(-7)
y=-42

x=-7
y=-42

8 0

3 years ago

Read 2 more answers

A typical marathon is 26.2 miles. Allan averages 12 kilometers per hour when running in marathons. Determine how long it would t

Natali [406]

Answer:

The time taken by Allan to complete the marathon 3.5 hours

Step-by-step explanation:

Given as :

The distance cover in marathon = d = 26.2 miles

∵ 1 mile = 1.609 km

So, d = 26.2 × 1.609 km

i.e d = 42.155 kilo meter

The average speed of Allan = s = 12 km per hour

Let the time taken by Allan to complete the marathon = t hours

Now, ∵ Time = $\dfrac{\textrm Distance}{\textrm Speed}$

Or, t = $\dfrac{\textrm d}{\textrm s}$

Or, t = $\dfrac{\textrm 42.155 km}{\textrm 12 kmph}$

or, t = 3.512 hours

So , The time taken by Allan to complete the marathon = t = 3.5 hours

Hence, The time taken by Allan to complete the marathon 3.5 hours Answer

4 0

3 years ago

<img src="https://tex.z-dn.net/?f=-2%5Csqrt%7B18%7D%20%2B2%5Csqrt%7B2%7D" id="TexFormula1" title="-2\sqrt{18} +2\sqrt{2}" alt="-

UkoKoshka [18]

Answer:

- 4 $\sqrt{2}$

Step-by-step explanation:

Using the rule of radicals

$\sqrt{a}$ × $\sqrt{b}$ ⇔ $\sqrt{ab}$

Simplify $\sqrt{18}$ using this rule

$\sqrt{18}$

= $\sqrt{9(2)}$

= $\sqrt{9}$ × $\sqrt{2}$ = 3 $\sqrt{2}$

Then

- 2 $\sqrt{18}$ + 2 $\sqrt{2}$

= - 2(3 $\sqrt{2}$ ) + 2 $\sqrt{2}$

= - 6 $\sqrt{2}$ + 2 $\sqrt{2}$

= - 4 $\sqrt{2}$

5 0

3 years ago

Find the area between y = 8 sin ( x ) y=8sin⁡(x) and y = 8 cos ( x ) y=8cos⁡(x) over the interval [ 0 , π ] . [0,π]. (Use decima

Marina86 [1]

Answer:

0.416 au

Step-by-step explanation:

Let y1=8sin(x) and y2=8cos(x), we must find the area between y1 and y2

$\int\limits^\pi _0{(8cos(x)-8sin(x))} \, dx = 8\int\limits^\pi _0{(cos(x)-sin(x))} \, dx =\\8(sin(x)+cos(x)) evaluated(0-\pi )=\\8(sin(\pi )-sin(0))+8(cos(\pi )-cos(0))=\\8(0.054-0)+8(0.998-1)=8(0.054)+8(-0.002)=0.432-0.016=0.416$

3 0

3 years ago