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ollegr [7]
2 years ago
10

In 1950, scientist estimated a certain animal population in a particular geographical area to be 6400 in 2000, the population ha

d risen to 7200. If this animal population experiences the same % increase over the next 50yrs what will be approximate population be?
Mathematics
1 answer:
irina1246 [14]2 years ago
7 0

Answer:

8,100

Step-by-step explanation:

7,200 - 6,400 = 800 increased in 50. Years

What percentage is 800 of 6,400 (%/100 = is/of)

x/100 = 800/6400 (cross multiply)

(800*100)/6400 = 12.50%

(12.50 * 7200)/100 = 900 increased

7,200 + 900 = 8,100

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Add 77 -10 with its additive inverse.​
Ganezh [65]

Answer: 77 - 10 = 67, and the additive inverse of 77 - 10 is 77 + 10. 77 + 10 = 87.

Hope this helps! This question was kind of confusing for me, because I didn’t understand why you said to add 77 - 10… is this is the incorrect answer sorry your question was worded weird

4 0
2 years ago
Help:(!!.!.!.!.!.!!.!.
andre [41]

Answer:

Step-by-step explanation:

10(5)=50

7 0
2 years ago
Read 2 more answers
7.7.33
GenaCL600 [577]
We know that

At sea level, the height is 0 and
the pressure is 98 kilopascals

At 1000 ft, the height is 1000 and
the pressure <span>decreases about 11.41%

</span>i(100%-11.41%)/100----> (0.8859)

therefore
1) at 1000 ft--------> the pressure is 98*(0.8859)----------> 86.82 kilopascals
2) at 2000 ft--------> the pressure is 86.82*(0.8859)-------> 76.91 kilopascals
3) at 3000 ft--------> the pressure is 76.91*(0.8859)-------> 68.14 kilopascals
4) at 4000 ft---------> the pressure is 68.14*(0.8859)-------> 60.36 kilopascals


the answer is
<span>The pressure at an altitude of 4000 m is about </span>60.36 kilopascals
7 0
3 years ago
If 10 is added to each observation and the following data set what is the relationship between the original standard deviation a
jeyben [28]

Answer:

g

Step-by-step explanation:

7 0
2 years ago
The researcher has limited resources. He sends 9 emails from a Latino name, and 14 emails from a non-Latino name. For the Latino
deff fn [24]

Answer: 38.41 minutes

Step-by-step explanation:

The standard error for the difference in means is given by :-

SE.=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma^2_2}{n_2}}

where , \sigma_1 = Standard deviation for sample 1.

n_1= Size of sample 1.

\sigma_2 = Standard deviation for sample 2.

n_2= Size of sample 2.

Let the sample of Latino name is first and non -Latino is second.

As per given , we have

\sigma_1=82

n_1=9

\sigma_2=101

n_2=14

The standard error for the difference in means will be :

SE.=\sqrt{\dfrac{(82)^2}{9}+\dfrac{(101)^2}{14}}

SE.=\sqrt{\dfrac{6724}{9}+\dfrac{10201}{14}}

SE.=\sqrt{747.111111111+728.642857143}

SE.=\sqrt{1475.75396825}=38.4155433158\approx38.41

Hence, the standard error for the difference in means =38.41 minutes

3 0
2 years ago
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