Using the discrete probability outputs given in the attached table ; the probability values of having exactly 6 ; and having 6 or more girls are :
<u>The </u><u>probability</u><u> of having </u><u>exactly 6 girls</u><u> can be defined as</u> :
- P(X = 6) = 0.111 (from the discrete probability table)
2.)
<u>The </u><u>probability</u><u> of having </u><u>6 or more</u><u> girls can be defined as</u> :
- P(X ≥ 6) = P(X = 6) + P(X = 7) + P(X = 8)
- From the table attached :
- P(X ≥ 6) = 0.111 + 0.014 + 0.003 = 0.1
Therefore, the probability of having exactly 6 girls is 0.111 while the probability of having 6 or more girls is 0.1
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Answer:
8
Step-by-step explanation:
10+8-3+5-12=
Answer:
1) Combine like terms
2) ![\sqrt[3]{x} =3](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%7D%20%3D3)
3) cube both sides of the equation
4) ![4\sqrt[3]{27} +8\sqrt[3]{27}=36](https://tex.z-dn.net/?f=4%5Csqrt%5B3%5D%7B27%7D%20%2B8%5Csqrt%5B3%5D%7B27%7D%3D36)
5) 4(3) + 8(3) = 36
Step-by-step explanation:
1) Combine like terms
2) ![\sqrt[3]{x} =3](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%7D%20%3D3)
3) cube both sides of the equation
4) ![4\sqrt[3]{27} +8\sqrt[3]{27}=36](https://tex.z-dn.net/?f=4%5Csqrt%5B3%5D%7B27%7D%20%2B8%5Csqrt%5B3%5D%7B27%7D%3D36)
5) 4(3) + 8(3) = 36
Hello,
Your answer would be:
75%
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