A concession stand uses 1/48 of a package of lemonade mix to make 1/6 gallons of lemonade.

Bill paid $45.35 in tax on a laptop that cost $589. About what percent sales tax did Bill pay?

Softa [21]

Answer:

267.1115

Step-by-step explanation:

3 0

3 years ago

Help! Will give crown to the most helping

kolbaska11 [484]

The first one seems more reasonable

8 0

3 years ago

Can anyone help me please??? It’s not online. And please keep scrolling if u don’t know ...

lions [1.4K]

Answer:

Step-by-step explanation:

slopes and equations:

find the equation thur ( 6,1 ) and (-2,-3)

find the slope m

m = (y2-y1) / (x2-x1 )

m = (-3 - 1) / (-2 -6)

m = -4 / -8

m = 1/2

now use the point-slope formula with our known slope

y-y1 = m(x-x1)

y-1 = 1/2(x-6)

y - 1 = 1/2x -3

y = 1/2x -3 +1

y = $\frac{1}{2}$ x -2

Find the equation parallel to y = 3x + 6 and thur (0,1)

Parallel means the same slope, the slope is 3 for the equation above.

use the slope-intercept formula again with the point given and the slope 3

y-1 = 3(x -0)

y - 1 = 3x

y = 3x +1

Find the equations perpendicular to 2x + y = 8 and the same y intercept as 4y = x + 3.

put both equations into proper form

y = -2x +6

y = $\frac{1}{4}$ x + $\frac{3}{4}$

perpendicular means reciprocal slope and change the sign, the 2nd equation has an intercept of $\frac{3}{4}$ , so

y = 1/2x + $\frac{3}{4}$

there you go Amanda :)

8 0

3 years ago

What is 4 x 10 to the third power written in STANDARD FORM!!!!!!!!!!!!!!!!!!!!

GuDViN [60]

Answer:

(4x10)^3=64,000

Step-by-step explanation:

p please mark brainliest

6 0

3 years ago

Read 2 more answers

For integers a, b, and c, consider the linear Diophantine equation ax C by D c: Suppose integers x0 and y0 satisfy the equation;

Dmitrij [34]

Answer:

a.

$x = x_1+r(\frac{b}{gcd(a, b)} )\\y=y_1-r(\frac{a}{gcd(a, b)} )$

b. x = -8 and y = 4

Step-by-step explanation:

This question is incomplete. I will type the complete question below before giving my solution.

For integers a, b, c, consider the linear Diophantine equation

$ax+by=c$

Suppose integers x0 and yo satisfy the equation; that is,

$ax_0+by_0 = c$

what other values

$x = x_0+h$ and $y=y_0+k$

also satisfy ax + by = c? Formulate a conjecture that answers this question.

Devise some numerical examples to ground your exploration. For example, 6(-3) + 15*2 = 12.

Can you find other integers x and y such that 6x + 15y = 12?

How many other pairs of integers x and y can you find ?

Can you find infinitely many other solutions?

From the Extended Euclidean Algorithm, given any integers a and b, integers s and t can be found such that

$as+bt=gcd(a,b)$

the numbers s and t are not unique, but you only need one pair. Once s and t are found, since we are assuming that gcd(a,b) divides c, there exists an integer k such that gcd(a,b)k = c.

Multiplying as + bt = gcd(a,b) through by k you get

$a(sk) + b(tk) = gcd(a,b)k = c$

So this gives one solution, with x = sk and y = tk.

Now assuming that ax1 + by1 = c is a solution, and ax + by = c is some other solution. Taking the difference between the two, we get

$a(x_1-x) + b(y_1-y)=0$

Therefore,

$a(x_1-x) = b(y-y_1)$

This means that a divides b(y−y1), and therefore a/gcd(a,b) divides y−y1. Hence,

$y = y_1+r(\frac{a}{gcd(a, b)})$ for some integer r. Substituting into the equation

$a(x_1-x)=rb(\frac{a}{gcd(a, b)} )\\gcd(a, b)*a(x_1-x)=rba$

or

$x = x_1-r(\frac{b}{gcd(a, b)} )$

Thus if ax1 + by1 = c is any solution, then all solutions are of the form

$x = x_1+r(\frac{b}{gcd(a, b)} )\\y=y_1-r(\frac{a}{gcd(a, b)} )$

In order to find all integer solutions to 6x + 15y = 12

we first use the Euclidean algorithm to find gcd(15,6); the parenthetical equation is how we will use this equality after we complete the computation.

$15 = 6*2+3\\6=3*2+0$