The measure of a single angle of a triangle is not enough information to allow you to find any other angle or side length of the triangle. Is there more information or a figure?
If this triangle is a right triangle, and angle C is the right angle, then angle C measures 90.
The sum of the measures of the angles of a triangle is 180.
m<A + m<B + m<C = 180
We know angle A measures 48.
Angle C measures 90.
48 + m<B + 90 = 180
m<B + 138 = 180
m<B = 42
Answer:
1. 2x + 8y = 10xy
2. 13ab + 15ab = 28ab
Step-by-step explanation:
This is because for question 2 the "a" and "b" stay together since it's on 13 and 15. So that is why you would get 28ab. For question 1 it's basicly the same but instead, you combine the two to get your answer.
Hope this helps.
Answer:
c) Statistically significant results that are the opposite to what was hypothesized are likely the result of a Type II error.
Step-by-step explanation:
Which statement is true?
statistically significant results are results of a null hypothesis that is true. while
Type 2 error is the error that occur when one fails to reject a null hypothesis that is wrong.
therefore, Statistically significant results that are the opposite to what was hypothesized, is a type 2 error, because it is false.
c) Statistically significant results that are the opposite to what was hypothesized are likely the result of a Type II error.
Answer: C
Step-by-step explanation:
Range is the difference between the lowest and highest number so it should be C due to the lowest being 9 and the highest being 33, so 33-9 is 24.
Answer:
In order to find the variance we need to calculate first the second moment given by:
And the variance is given by:
![Var(X) = E(X^2) +[E(X)]^2 = 23.36 -[4.74]^2 = 0.8924](https://tex.z-dn.net/?f=%20Var%28X%29%20%3D%20E%28X%5E2%29%20%2B%5BE%28X%29%5D%5E2%20%3D%2023.36%20-%5B4.74%5D%5E2%20%3D%200.8924)
And the deviation would be:
Step-by-step explanation:
Previous concepts
The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.
The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).
Solution to the problem
For this case we have the following distribution given:
X 3 4 5 6
P(X) 0.07 0.4 0.25 0.28
We can calculate the mean with the following formula:
In order to find the variance we need to calculate first the second moment given by:
And the variance is given by:
And the deviation would be:
