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3 years ago

6. Write the equation of the line.

Mathematics

1 answer:

liberstina [14]3 years ago

4 0

Answer:

y = x + 2

Step-by-step explanation:

As the equation of a line is in the form y = mx + c:

Step 1 - Calculate the y intercept

This can be done by looking at the y coordinate where x = 0:

y = mx + c

In the picture, the y intercept is 2 so:

y = mx + 2

Step 2 - Calculate the slope

This can be calculated by:

$\frac{\text{change in y}}{\text{change in x}}$

Get two sets of coordinates:

(0, 2) and (2, 4)

Calculate the changes by subtracting from one another:

$\frac{4 - 2}{2 - 0} \\\frac{2}{2}\\=1$

So the gradient is 1, meaning the equation of the line is:

$y = 1x + 2 \\\text{or}\\y = x + 2$

Hope this helps!

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4 years ago

Let X be a continuous random variable with density functionf(x)={1−|x|0 for −1

BlackZzzverrR [31]

Answer:

$f_Y (y) =\frac{d}{dy} = 2 \frac{1}{2 |\sqrt{y}|} -1 = \frac{1}{|\sqrt{y}|} -1,0 \leq Y\leq 1$

Step-by-step explanation:

For this case we want to find the density function for $Y=X^2$

And we have the following density function for the random variable X:

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So we can do this replacing $Y=X^2$

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And if we integrate we got this:

$F_Y (y) = [t+ \frac{t^2}{2}] \Big|_{-\sqrt{y}}^0+ [t -\frac{t^2}{2}] \Big|_{0}^{\sqrt{y}}$

And replacing we got:

$F_Y (y) = [0 -(-\sqrt{y} +\frac{y}{2})] + [\sqrt{y} -\frac{y}{2}]$

$F_Y (y) = 2 |\sqrt{y}| -y$

And if we want to find the density function we just need to derivate the pdf like this:

$f_Y (y) =\frac{d}{dy} = 2 \frac{1}{2 |\sqrt{y}|} -1 = \frac{1}{|\sqrt{y}|} -1,0 \leq Y\leq 1$

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4 years ago

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4 years ago

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FromTheMoon [43]

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4 years ago

Read 2 more answers

6. Write the equation of the line. ​

6. Write the equation of the line.