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maksim [4K]
3 years ago
9

Find the unknown value.

Mathematics
2 answers:
statuscvo [17]3 years ago
7 0

\frac{15}{?}  =  \frac{5}{10}  \\  =  \frac{5}{10}  \times 15 \\  =  \frac{5}{2}  \times 3 \\  = 30

Dafna11 [192]3 years ago
6 0
The unknown value is 30
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EMERGENCY QUESTION! No Decimal answers plz!
telo118 [61]

Answer:

1,145,375 cm³

Step-by-step explanation:

Like with an earlier question you had, there is a chunk missing. If that chunk was filled in, this would be a 205 * 70 * 85 rectangular prism.

205 * 70 * 85

17,425 * 70

1,219,750

The cut out chunk is a 25 * 70 * 85 triangular prism.

1/2 (25 * 70 * 85)

1/2(2,125 * 70)

1/2(148,750)

74,375

Now that we know what the cut-out chunk is, subtract that from the first value we got.

1,219,750 -74,375

1,145,375 cm³

The volume of the Canadian Post mailbox is 1,145,375 cm³.

8 0
3 years ago
Read 2 more answers
a waiter had nine tables he was waiting on, with seven women and three men at each table. how many customees total did the waite
Greeley [361]
Since each table had 7 women and 3 men at each table, that would mean each table has 10 people. Since there are 9 tables he was waiting on, and 10 people at each table, multiply 9 x 10, and you will find that he served 90 people in total.

8 0
3 years ago
Read 2 more answers
How many times can 6 go into 58
swat32
58 ÷ 6 = 9/2/3

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4 0
3 years ago
What is your sister’s total cost under each of the two plans?2. Suppose your sister doubles her monthly usage to 3,500 minutes a
chubhunter [2.5K]

Answer:

(1) The total cost under Plan A is <u>$92</u> and the total cost under Plan B is <u>$515</u>.

(2) The total cost under Plan A is <u>$92</u> and the total cost under Plan B is <u>$1,030</u>.

Step-by-step explanation:

<u><em>The question is incomplete, so the complete question is below:</em></u>

A\ cell \ phone \ company\  offers\  two \ different \ plans.

Plan\ A\ costs\ \$92\ per\ month\ for\ unlimited\ talk\ and\ text.\ Plan\ B\ costs \ $0.20\ per\ minute\ plus\ \$0.10\ per\ text\ message\ sent.You\  need \  to\   purchase \  a \  plan \  for\   your \  14-year-old \  sister.Your\  sister\  currently \ uses\  1,750 \ minutes\  and \ sends\  1,650 \ texts\  each \ month.(1) What\  is\   your \  sister's\   total\   cost\   under \  each\   of\   the\   two\   plans?

(2) Suppose\  your\  sister\  doubles\  her\  monthly\  usage \ to\  3,500\  minutes \ and\  sends\  3,300 \ texts.What \ is \  your  \ sister's \  total \  cost \  under \  each \  of  \ the \  two \  plans?

Now, to find (1) total cost for each of the two plans. (2) Total cost under each of the two plans, if sister doubles her monthly usage to 3,500 minutes and sends 3,300 texts.

<h3>(1) </h3>

As, the Plan A is for unlimited talk and text

Cost of the Plan A = $92.

<u><em>Now, to find the cost under Plan B:</em></u>

According to question:

Rate of call per minute is $0.20 and per text is $0.10.

Calls she uses currently is 1,750 minutes and text 1,650.

<u><em>So, to get the cost of Plan B:</em></u>

0.20\times 1750+0.10\times 1650

=350+165

=515.

Thus, Plan B costs $515.

<h3>(2)</h3>

<u><em>Now, to get the total cost as, sister doubles her monthly usage to 3,500 minutes and sends 3,300 texts.</em></u>

As, the Plan A is same in both cases and is for unlimited text and calls.

So, cost of Plan A = $92.

As, the monthly usage is double.

Calls in minutes are 3,500.

Texts are 3,300.

<u><em>Now, to get the total cost under Plan B:</em></u>

0.20\times 3500+0.10\times 3300

=700+330

=1030.

Hence, the cost of Plan B = $1,030.

Therefore, (1) The total cost under Plan A is $92 and the total cost under Plan B is $515.

(2) The total cost under Plan A is $92 and the total cost under Plan B is $1,030.

7 0
3 years ago
Express a decimal number ( ie 0.768) - process description please - as a rational number (96/125)?
Stels [109]

The decimal representation of any number is a linear combination of powers of 10. In other words, given a number like 123.456, we can expand it as

1\cdot10^2+2\cdot10^1+3\cdot10^0+4\cdot10^{-1}+5\cdot10^{-2}+6\cdot10^{-3}

10^{-n}=\dfrac1{10^n} for any n, so the above is the same as

100+20+3+\dfrac4{10}+\dfrac5{100}+\dfrac6{1000}=\dfrac{100000+20000+3000+400+50+6}{1000}=\dfrac{123456}{1000}

Similarly, we can write

0.768=\dfrac{768}{1000}

Now it's a question of reducing the fraction as much as possible. We have \mathrm{gcd}(768,1000)=8 so

\dfrac{768}{1000}=\dfrac{96\cdot8}{125\cdot8}=\dfrac{96}{125}

5 0
3 years ago
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