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Kruka [31]
3 years ago
15

See this ketchup package,It cost 1.50$ to make the package but the ketchup inside the package cost a $1more than the ketchup pac

kage. How much does the package cost??
Mathematics
1 answer:
Vaselesa [24]3 years ago
5 0

Answer:

15.+1.5+1=4 dollor

Step-by-step explanation:

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What is the absolute value of -6 please help
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4 0
3 years ago
The women of latvia are the tallest in the world with an average height of 170 cm, which is what in feet and inches?.
Leto [7]

Step-by-step explanation:

Convert the given value in cm into feet and inches.

<u>Use the unit rates:</u>

  • 1 foot = 30.48 cm
  • 1 inch = 2.54 cm

<u>Convert:</u>

  • 170 cm = 170/30.48 feet = 5.58 feet (rounded)
  • 170 cm = 170/2.54 inches = 66.93 inches

or

  • 170 cm = 5 feet and 17.6 cm = 5 feet and 7 inches (rounded)
6 0
3 years ago
The average student loan debt for college graduates is $25,150.
Aleks04 [339]

Using the normal distribution, it is found that:

a) X \approx N(25150, 12050)

b) There is a 0.5859 = 58.59% probability that the college graduate has between $14,200 and $33,950 in student loan debt.

c) Low: $23,519.65, High: $26,580.35.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

\mu = 25150, \sigma = 12050.

Hence the distribution of X can be described as follows:

X \approx N(25150, 12050)

The probability that the college graduate has between $14,200 and $33,950 in student loan debt is the <u>p-value of Z when X = 33950 subtracted by the p-value of Z when X = 14200</u>, hence:

X = 33950:

Z = \frac{X - \mu}{\sigma}

Z = \frac{33950 - 25150}{12050}

Z = 0.73

Z = 0.73 has a p-value of 0.7673.

X = 14200:

Z = \frac{X - \mu}{\sigma}

Z = \frac{14200 - 25150}{12050}

Z = -0.91

Z = -0.91 has a p-value of 0.1814.

0.7673 - 0.1814 = 0.5859.

There is a 0.5859 = 58.59% probability that the college graduate has between $14,200 and $33,950 in student loan debt.

Considering the symmetry of the normal distribution, the middle 10% is between the 45th percentile(X when Z = -0.127) and the 55th percentile(X when Z = 0.127), hence:

Z = \frac{X - \mu}{\sigma}

-0.127 = \frac{X - 25150}{12050}

X - 25150 = -0.127(12050)

X = $23,519.65.

Z = \frac{X - \mu}{\sigma}

0.127 = \frac{X - 25150}{12050}

X - 25150 = 0.127(12050)

X = $26,580.35.

More can be learned about the normal distribution at brainly.com/question/4079902

#SPJ1

5 0
2 years ago
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