There is no picture? this doesn't really make sense <span />
1) 6÷0.2 = 30
If 6/2=3 then 6/0.2=30 as the decimal place shifts one place.
2)8÷0.1 = 80
8/1=8 so shift the decimal place over once to make 80.
3)9÷0.3 = 30
9/3=3 so shift the decimal place over once to get 30.
4)4÷0.04 = 100
4/4=1 so shift the decimal place over twice to get 100.
5)7÷0.002 = 3500
7/2=3.5 so shift the decimal place over three times to get 3500
6)0.718÷0.2 = 3.59
718/2=359 so shift the decimal over three places for the 0.718 and then back over once for the 0.2
7)0.0141÷0.003 = 4.7
141/3=47 so shift the decimal over our times for the 0.0141 and then back over three times for the 0.003
8)0.24÷0.012 = 20
24/12=2 so shift the decimal point over once twice for 0.24 then back over three times for 0.012
9)1.625÷0.0013 = 1250
1625/13=125 so shift the decimal point over three times for the 1.625 and then back four times for the 0.0013
10)47.1÷0.15 = 314
471/15=31.4 so shift the decimal point over once for the 47.1 and then back over twice for the 0.15.
Hope this helps :)
Answer:
3a+6
Step-by-step explanation:
3a+6 = 24a+48 divided by 8 (there are 8 sides in an octagon)
covert 24a +48 inches into feet
2a+4 feet = 18 feet
subtract 4 from both sides
2a = 14
divided 2 from both sides
a = 7
covert 3a+6 inches into feet
0.25a +0,5
0.25(7)+0.5
= 2.25
verify your answer
2.25 x 8 = 18
Answer:
The value of the standard error for the point estimate is of 0.0392.
Step-by-step explanation:
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean 
and standard deviation 
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean and standard deviation 
.
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean 
and standard deviation 
In a randomly selected sample of 100 students at a University, 81 of them had access to a computer at home.
This means that 
Give the value of the standard error for the point estimate.
This is s. So
The value of the standard error for the point estimate is of 0.0392.
9 is the answer negatives cancel out creating positve
