Question

5r^2-13r-6=0 How do I solve this

Answer 1

$5 {r}^{2} - 13r - 6 = 0 \\ a = 5 \\ b = - 13 \\ c = - 16$

r= -(-13)±>

$\sqrt{( - 13) {}^{2} } - 4.5( - 6)$

2.5

r= 13±17

10

r=13+17

10

r=13-17

10

$r = 2 \\ r = \frac{ - 2}{5}$

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Answer 2

Answer: you need to factor then you can solve