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IgorLugansk [536]
2 years ago
12

5r^2-13r-6=0 How do I solve this

Mathematics
2 answers:
frosja888 [35]2 years ago
7 0

5 {r}^{2}  - 13r - 6 = 0 \\ a = 5 \\ b =   - 13 \\ c =  - 16 \\

<em>r</em><em>=</em><em> </em><em><u>-</u></em><em><u>(</u></em><em><u>-</u></em><em><u>1</u></em><em><u>3</u></em><em><u>)</u></em><em><u>±</u></em><em><u>></u></em>

<em><u>\sqrt{( - 13) {}^{2} }  - 4.5( - 6)</u></em>

<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>2</em><em>.</em><em>5</em>

<em>r</em><em>=</em><em> </em><em><u>1</u></em><em><u>3</u></em><em><u>±</u></em><em><u>1</u></em><em><u>7</u></em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>1</em><em>0</em>

<em>r</em><em>=</em><em><u>1</u></em><em><u>3</u></em><em><u>+</u></em><em><u>1</u></em><em><u>7</u></em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em>1</em><em>0</em>

<em>r</em><em>=</em><em><u>1</u></em><em><u>3</u></em><em><u>-</u></em><em><u>1</u></em><em><u>7</u></em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em>1</em><em>0</em>

<em>r = 2 \\ r =  \frac{ - 2}{5}</em>

<em>this \: the \: answer \: your \: question \\  \\ mark \: me \: as \: a \: brainlist \: plz</em>

nignag [31]2 years ago
7 0
Answer: you need to factor then you can solve

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<u> ∑ k = 1 88 2.5 ⁢ ( 1.2 ) k</u><u>  is this series written in </u><u>sigma notation. </u>

What is the series written in sigma notation?

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Given:

2.5 + 2.5(1.2) + 2.5(1.2)2 + ⋯ + 2.5(1.2)87

If we look at the power it is always one less the term i.e., for first term the value of k=0.

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Step-by-step explanation:

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