Given:
A line passes through (-5,-3) and perpendicular to .
To find:
The equation of the line.
Solution:
We have,
On comparing this equation with slope intercept form, i.e., , we get
It means, slope of this line is .
Product of slopes of two perpendicular lines is always -1.
Slope of required line is and it passes through the point (-5,-3). So, the equation of the line is
where, m is slope.
Therefore, the equation of required line is .
Answer:
f(x) = 3 cos (2Pi / period value ; x )+ 2
or see answer using 2 as the period see answer in bold below.
Step-by-step explanation:
cosine function amplitude of 3 is A = 3
The period is used to find B
You need to show period value as the denominator and work out from there with 2PI as a function numerator to show as 2pi / period can be a data angle
C is the adding value.
Acos (Bx) + C
A = 3
Bx = 2 pi / period
C = + 2
However f 2 is also the period found
then we just plug in 2 to above formula
f(x) = 3 cos (2Pi / 2 ; x )+ 2
f(x) = 3cos (x pi) + 2
