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vodomira [7]
3 years ago
15

In the given figure PQ is a transversal intersecting lines AB and CD. Find the measures of angles x and y. Hence prove AB//CD.​

Mathematics
1 answer:
tekilochka [14]3 years ago
3 0

<u>Explanation</u><u>:</u>

From the given figure ,

AB || CD

PQ is a transversal

Given angles are 50° and 130°

50° and x are linear pair

⇛ 50°+x = 180°

⇛ x = 180°-50°

⇛ x = 130°

Therefore, "x" = 130°

and

130° and y are vertically opposite angles which are equal.

⇛ "y" = 130°

Therefore, y = 130°

<u>Additional</u><u> </u><u>comment</u><u>:</u><u>-</u>

  1. If two parallel lines Intersected by a transversal then
  2. Corresponding angles are equal.
  3. Vertically Opposite angles are equal.
  4. The sum of two adjacent angles is equal to 180° then they are called Linear Pair.

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Imagine that you have entered the following distribution of scores into the program: 7, 9, 6, 3, 7, 8, 4, 10, 7, 9. The mean of
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3

Step-by-step explanation:

Mean refers to the average value of the set of data.

It is the central value of the set of data.

Another word for Mean is average.

Given scores:7, 9, 6, 3, 7, 8, 4, 10, 7, 9

Solution:

Sum of observations = 7+ 9+ 6+ 3+ 7+ 8+ 4+ 10+ 7+ 9=70

Number of observations = 10

Mean = Sum of observations/Number of observations = \frac{70}{10}=7

If observation 3 is removed:

Sum of observations = 7+ 9+ 6+  7+ 8+ 4+ 10+ 7+ 9=67

Number of observations = 9

Mean =  Sum of observations/Number of observations = \frac{67}{9}=7.44

If observation 4 is removed:

Sum of observations = 7+ 9+ 6+ 3+ 7+ 8+ 10+ 7+ 9=66

Number of observations = 9

Mean = \frac{66}{9}=7.3

If observation 6 is removed:

Sum of observations = 7+ 9+ 3+ 7+ 8+ 4+ 10+ 7+ 9=64

Number of observations = 9

Mean = \frac{64}{9}=7.1

If observation 7 is removed:

Sum of observations = 9+ 6+ 3+  8+ 4+ 10+  9=49

Number of observations = 7

Mean = \frac{49}{7}=7

If observation 8 is removed:

Sum of observations = 7+ 9+ 6+ 3+ 7+  4+ 10+ 7+ 9=62

Number of observations = 9

Mean = \frac{62}{9}=6.9

If observation 9 is removed:

Sum of observations = 7+ 6+ 3+ 7+ 8+ 4+ 10+ 7=52

Number of observations = 8

Mean = \frac{52}{8}=6.5

If observation 10 is removed:

Sum of observations = 7+ 9+ 6+ 3+ 7+ 8+ 4+ 7+ 9=60

Number of observations = 9

Mean = \frac{60}{9}=6.7

Therefore, mean of this distribution of scores would be changed the most if a score 3 was removed from the data set.

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