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suter [353]
3 years ago
8

Please sagot mo to thanks na lang​

Mathematics
1 answer:
WITCHER [35]3 years ago
6 0

Answer:

1. A

2.C

3.A

4.B

5.C

Hope That helped lods!:)

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The 90% confidence interval for the population proportion of all such firms with this as the primary motivation is (69.96%, 80.04%).

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In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

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90% confidence level

So \alpha = 0.1, z is the value of Z that has a p-value of 1 - \frac{0.}{2} = 0.975, so Z = 1.645.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.75 - 1.645\sqrt{\frac{0.75*0.25}{200}} = 0.6996

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.75 + 1.645\sqrt{\frac{0.75*0.25}{200}} = 0.8004

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3 years ago
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