Question

Please help solve this:27x^2 + 15x + 10 = 0I don't get what I need to do.​

Answer 1

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

Let's solve for x :

• $27 {x}^{2} + 15x + 10 = 0$

Using quadratic formula ~

$\boxed{ \frac{ - b \pm \sqrt{b {}^{2 } - 4ac}}{2a} }$

where,

• b = 15

• a = 27

• c = 10

let's find the roots ~

• $\dfrac{ - 15 \pm \sqrt{( {15})^{2} - (4 \times 27 \times 10)} }{(2 \times 27)}$

• $\dfrac{ - 15 \pm \sqrt{225 - 1080} }{54}$

• $\dfrac{ - 15 \pm \sqrt{ - 855} }{54}$

• $\dfrac{ - 15 \pm3 \sqrt{95} \: i}{54}$

• $\dfrac{ - 15}{54} \pm \dfrac{3 \sqrt{95} }{54} i$

• So, the required roots are ~

$x = - \dfrac{5}{18} + \dfrac{3 \sqrt{95} }{54}$

and

$x = - \dfrac{5}{18} - \dfrac{3 \sqrt{95} }{54}$

There is no real roots, both the roots are imaginary ~

Answer 2

Answer:

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