3 years ago

Help what is the temperature

Mathematics

1 answer:

mote1985 [20]3 years ago

7 0

The answer is 25 degrees Celsius

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Chang knows one side of a triangle is 13 cm. Which set of two sides is possible for the lengths of the other two

Ne4ueva [31]

Answer:

7 cm and 2 cm

Step-by-step explanation:

the other possible sides add up to more than 13, therefore it cannot be possible to make a triangle with them. Triangle Inequality Theorem.

6 0

3 years ago

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PLEASE HELP asap it’s for a quiz if you know at least one answer please tell me

VARVARA [1.3K]

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3 years ago

A 100 foot ladder is leaning against a tree so that the top of the ladder is 96 feet above the ground. How far is the base of th

ahrayia [7]

Answer:The base of the ladder from the tree is 28ft

Step-by-step explanation:

Using pythagorean theorem

Let 100ft= hypothesis is the right angle triangle

Let 96ft be the height of the ladder

Let x be the base of the right angle triangle between the base of the ladder and the tree

h^2=a^2+b^2

100^2=96^2 +b^2

10,000=9216 +b^2

b^2=10,000-9216

b=sqrt(784)

b=28ft

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4 years ago

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When fractions share the same number on the bottom they have a?

Snezhnost [94]

Fractions that have the same number on the bottom have a "common denominator."

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3 years ago

What's the answer for this question? (The numbers after the letters are indexes btw) 27a9 x 18b5 x 4c2 Over 18a4 x 12b2 x 2c

zysi [14]

Answer:

$\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c} = \frac{9}{2}a^5b^3c$

Step-by-step explanation:

Given

$\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c}$

Required

Simplify

$\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c}$

Cancel out 18

$\frac{27a^9 * b^5 * 4c^2 }{a^4 * 12b^2 * 2c}$

Divide 4 and 2

$\frac{27a^9 * b^5 * 2c^2 }{a^4 * 12b^2 *c}$

Divide 27 and 12 by 3

$\frac{9a^9 * b^5 * 2c^2 }{a^4 * 4b^2 *c}$

Apply law of indices

$\frac{9a^{9-4} * b^{5-2} * 2c^{2-1} }{4}$

$\frac{9a^5 * b^3 * 2c }{4}$

Divide 2 and 4

$\frac{9a^5 * b^3 * c}{2}$

$\frac{9a^5b^3c}{2}$

Rewrite as:

$\frac{9}{2}a^5b^3c$

Hence:

$\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c} = \frac{9}{2}a^5b^3c$

4 0

3 years ago