The answer is B. 5
6+2=8
3+5=8
X = -2
3 x -2 = -6
-6 -2= -8
|-8| = 8
-2 + 1= -1
|-1|=1
Answer:
B.
Step-by-step explanation:
Well we know that

so we can get the 2 outside of the radical

and we can get the x^2 outside too.

and we also can get y outside.
so we have:
![2x^{2}y\sqrt[5]{7xy^3}](https://tex.z-dn.net/?f=2x%5E%7B2%7Dy%5Csqrt%5B5%5D%7B7xy%5E3%7D)
Answer:
x=4
Step-by-step explanation:
Remove the parentheses and turn the 4-2x and make it into 4+2x candle the equal term -4 and should be left with x+6=2+2x then move the variable to the left and change the sign so it would be x-2x=2-6 and collect like terms so it would be -x=2-6 and then calculate that and get -x= -4
(sorry its alot)