Let X be the number of burglaries in a week. X follows Poisson distribution with mean of 1.9
We have to find the probability that in a randomly selected week the number of burglaries is at least three.
P(X ≥ 3 ) = P(X =3) + P(X=4) + P(X=5) + ........
= 1 - P(X < 3)
= 1 - [ P(X=2) + P(X=1) + P(X=0)]
The Poisson probability at X=k is given by
P(X=k) =
Using this formula probability of X=2,1,0 with mean = 1.9 is
P(X=2) =
P(X=2) =
P(X=2) = 0.2698
P(X=1) =
P(X=1) =
P(X=1) = 0.2841
P(X=0) =
P(X=0) =
P(X=0) = 0.1495
The probability that at least three will become
P(X ≥ 3 ) = 1 - [ P(X=2) + P(X=1) + P(X=0)]
= 1 - [0.2698 + 0.2841 + 0.1495]
= 1 - 0.7034
P(X ≥ 3 ) = 0.2966
The probability that in a randomly selected week the number of burglaries is at least three is 0.2966
Answer:
<h2>4 and 8</h2>
Step-by-step explanation:
4 and 8 are corresponding angles as they form at parallel lines cut by a transversal.
4 and 3 are supplementary angles (they both add up to 180°).
4 and 1 are vertically opposite angles and are equal to each other.
<u>From the above explanations, only 4 and 8 are corresponding angles. </u>
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Answer:
4 is a rational number
Step-by-step explanation:
rational numbers are numbers that can be divided by 2 and itself
Answer:
2:1
Step-by-step explanation: