Hello,
Let's assume a,b,c the 3 numbers
a+b+c=62
b=a-4
c=4*a
==>a+(a-4)+4a=62
==>6a=66
==>a=11
b=11-4=7
c=4*11=44
The 3 numbers are 11;7;44
Proofs:
11+7+44=62
7=11-4
44=4*11
Answer: 2.5
Step-by-step explanation:
Answer:
8w+5
Step-by-step explanation:
8*w=8w
8w+5
First you need to get rid of the parenthesis by distributing the 0.6 to each term inside.
(0.6)(10n) + (0.6)(25) =10+5n
6n +15 = 10+5n subtract the 5n on both sides and subtract 15 from both sides
6n-5n = 10-15
n=-5
True because it wouldn’t have made since if it was false
