Answer:
yes, It is
Step-by-step explanation:
Demonstrating the Pythagorean Theorem
When you think of each side of a right triangle as also being a side of a square that's attached to the triangle. The area of a square is any given side multiplied by itself. (For example, b x b = b^2).
In order to show that a^2 + b^2 = c^2,
follow these steps:
Get a right triangle on grid paper that you can print. You'll also need scissors, and a ruler.
Cut out the triangle.
Make three squares with sides that are equal to each side of the triangle. Begin with side
a. Measure the length of side a. On the blank piece of grid paper,
- draw a square with sides that are the same length as side a.
- Label this square a2.
- Repeat these steps to create squares for sides b and c. (If you don't have a ruler, just use the triangle as a guide; trace the length of one side, and then draw three more sides of the same length to make a square.)
Cut out the squares. Place each square next to the corresponding sides of the triangle.
Now show that a2 + b2 = c2. Place the squares made from sides a and b on top of square c. You will have to cut one of the squares to get a perfect fit.
Area of Whole Square
The total area of a big square, where each side having a length of a+b, is:
A = (a+b)(a+b)
Area of The Pieces
By adding up the areas of all the smaller pieces:
First, the smaller (tilted) square has an area of:c^2
Each of the four triangles has an area of: ab^2
So all four of them together is: 4ab^2 = 2ab
Adding up the tilted square and the 4 triangles gives: A = c^2 + 2ab
Both Areas Must Be Equal
The area of the large square is equal to the area of the tilted square and the 4 triangles. This can be written as:
(a+b)(a+b) = c^2 + 2ab
By rearrange this, we shall see if we can get the pythagoras theorem:
Start with:(a+b)(a+b) = c^2 + 2ab
Expand (a+b)(a+b): ag2 + 2ab + b^2 = c^2 + 2ab
Subtract "2ab" from both sides: a^2 + b^2 = c^2
Therefore, it's been proven that, a^2 + b^2 = C^2
PLS GIVE BRAIN :((
