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Kryger [21]
2 years ago
11

Tue 2 NOV moe.alefed.com 71. Check My Understanding 2 Khadija and Muneera are sisters. Together they have 15 dolls. Muneera has

4 times the number of dolls that Khadija has. Write and solve a system of equations to find how many dolls each girl has. Khadija has dolls. Muneera has​
Mathematics
1 answer:
tigry1 [53]2 years ago
5 0

Answer:

hhsnghh sihdg hhurihhspig

Step-by-step explanation:

shhgnshhistdh shdj

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It appears that people who are mildly obese are less active than leaner people. One study looked at the average number of minute
hoa [83]

Answer:

Obese people

Lower = \mu - 2\sigma = 373- 2(67) = 239

Upper = \mu + 2\sigma = 373+ 2(67) = 507

Lean People

Lower = \mu - 2\sigma = 526- 2(107) = 312

Upper = \mu + 2\sigma = 526+ 2(107) = 740

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, "almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ)".

Solution to the problem

Obese people

Let X the random variable that represent the minutes of a population (obese people), and for this case we know the distribution for X is given by:

X \sim N(373,67)  

Where \mu=373 and \sigma=67

On this case we know that 95% of the data values are within two deviation from the mean using the 68-95-99.7 rule so then we can find the limits liek this:

Lower = \mu - 2\sigma = 373- 2(67) = 239

Upper = \mu + 2\sigma = 373+ 2(67) = 507

Lean People

Let X the random variable that represent the minutes of a population (lean people), and for this case we know the distribution for X is given by:

X \sim N(526,107)  

Where \mu=526 and \sigma=107

On this case we know that 95% of the data values are within two deviation from the mean using the 68-95-99.7 rule so then we can find the limits liek this:

Lower = \mu - 2\sigma = 526- 2(107) = 312

Upper = \mu + 2\sigma = 526+ 2(107) = 740

The interval for the lean people is significantly higher than the interval for the obese people.

5 0
2 years ago
Find the measure of the are or angle indicated. Assume that lines which appear tanget are tangents. ​
Brilliant_brown [7]

9514 1404 393

Answer:

  1. 85°
  2. 60°

Step-by-step explanation:

1. Angle JKL is half the measure of the intercepted arc JK.

  (1/2)JK = 1/2(360° -190°) = (1/2)(170°) = 85°

  angle JKL is 85°

__

2. The angle between tangents is the supplement of the intercepted arc.

  angle JKL = 180° -(360° -240°)

  angle JKL = 60°

8 0
2 years ago
Alfonso has 435 stamps in his collection. He wants to collect at least 815 stamps. Write and
Lyrx [107]

Answer:

x= 361

Step-by-step explanation:

7 0
3 years ago
Calculate the Laplace transforms of the following from the definition. 1. y = t^2. y = t^3
Likurg_2 [28]

Answer:

1) L(y)=\frac{2}{s^{3}}

2) L(y)=\frac{6}{s^{4}}

Step-by-step explanation:

To find : Calculate the Laplace transforms of the following from the definition ?

Solution :

We know that,

Laplace transforms of t^n is given by,

L(t^n)=\frac{n!}{s^{n+1}}

1) y=t^2

Laplace of y,

L(y)=L(t^2) here n=2

L(y)=\frac{2!}{s^{2+1}}

L(y)=\frac{2}{s^{3}}

2) y=t^3

Laplace of y,

L(y)=L(t^3) here n=3

L(y)=\frac{3!}{s^{3+1}}

L(y)=\frac{3\times 2}{s^{4}}

L(y)=\frac{6}{s^{4}}

5 0
2 years ago
Can I actually get help and not people saying random stuff just for points????
loris [4]
Do you still need it?
8 0
2 years ago
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