Answer:
Step-by-step explanation:
yz+4z=z-y²
yz+4z-z=-y²
yz+3z=-y²
z(y+3)=-y²
Answer:
The number of times members and non-members will have to rent a boat in order to pay the same amount=20
Step-by-step explanation:
We can have two expressions to show the total cost paid by a member and non-member;
Total cost by member=Cost per summer season+cost per number of times they rent a boat×number of times they rent a boat
where;
Cost per summer season=$105
Cost per number of times they rent a boat=$9.50
Number of times they rent a boat=n
Replacing;
Total cost by a member=105+(9.5×n)=9.5 n+105......equation 1
Total cost by a non-member=Cost per number of times they rent a boat×number of times they rent a boat
where;
Cost per number of times they rent a boat=$14.75
Number of times they rent a boat=n
Replacing;
Total cost by a non-member=(14.75×n)=14.75 n......equation 2
To calculate the number of times they would have to rent a boat in order to pay the same amount, we equate equation 1 to equation 2
9.5 n+105=14.75 n
14.75 n-9.5 n=105
5.25 n=105
n=105/5.25
n=20
The number of times members and non-members will have to rent a boat in order to pay the same amount=20
Answer:
b = 9
Step-by-step explanation:
Using Pythagoras' identity in the right triangle.
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is
b² + 12² = 15²
b² + 144 = 225 ( subtract 144 from both sides )
b² = 81 ( take the square root of both sides )
b = 
= 9
Answer:
CI 95%(μ)= [13.506 ; 14.094]
Step-by-step explanation:
The confidence interval (CI) formula is:
CI (1-alpha) (μ)= mean+- [(Z(alpha/2))* σ/sqrt(n)]
alpha= is the proportion of the distribution tails that are outside the confidence interval. In this case, 5% because 100-90%
Z(5%/2)= is the critical value of the standardized normal distribution. In this case is 1.96
σ= standard deviation. In this case 0.75 day
mean= 13.8 days
n= number of observations
. In this case 25
Then, the confidence interval (90%) is:
CI 95%(μ)= 13.8+- [1.96*(0.75/sqrt(25)]
CI 95%(μ)= 13.8+- [1.96*(0.75/5)
]
CI 95%(μ)= 13.8+- (0.294)
CI 95%(μ)= [13.8-0.294 ; 13.8+0.294]
CI 95%(μ)= [13.506 ; 14.094]
