The mole fraction of the non-volatile solute in the solution is 0.13.
<h3>Mole fraction of solute </h3>
Using law of vapor pressure formula
Mole fraction of the non-volatile solute=Vapor pressure of the pure acetone-Vapor pressure of the solution /Vapor pressure of the pure acetone
Where:
Vapor pressure of the pure solvent (acetone) =266 torr
Vapor pressure of the solution =232torr
Mole fraction of solute = ?
Let plug in the formula
Mole fraction of the non-volatile solute=266-232/266
Mole fraction of the non-volatile solute=34/266
Mole fraction of the non-volatile solute=0.127
Mole fraction of the non-volatile solute=0.13 (Approximately)
Inconclusion the mole fraction of the non-volatile solute in the solution is 0.13.
Learn more about mole fraction of the non-volatile solute here: brainly.com/question/14114576
When the PH is 7.0, the hydronium Ion Concentration is gotten as; [H3O+] = 1 × 10^(-7) M
<h3>How to find the Concentration of an Ion? </h3>
The formula to find the pH of an Ion concentration is;
pH = - log [H3O+]
where;
[H3O+] is the molar concentration of hydronium ion.
We are told that the pH is 8.0. Thus;
8.0 = - log [H3O+]
10^(-8) = [H3O+]
[H3O+] = 1 × 10^(-8) M
Thus, when pH = 7.0, we have;
7.0 = - log [H3O+]
[H3O+] = 1 × 10^(-7) M
Complete question is;
When the fish-tank water has a pH of 8.0, the hydronium ion concentration is 1.0 × 10-8 mole per liter. What is the hydronium ion concentration when the water has a pH of 7.0?
Read more about Ion Concentration at; brainly.com/question/3997048
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Answer:
ANSWER IS
Explanation:
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