A. F(x)= 3x+6 =12
3x = 12-6
3x = 6
x=2
B. x=10, f(x)= 3*10+6 = 30+6 = 36
C. f(x) = 3x+6 = 6
3x = 6-6
3x=0
x=0
D. x=5, f(x) = 3x+6 = 3*5+6 = 15+6 = 21
Answer:
True
Step-by-step explanation:
Type I and Type II are not independent of each other - as one increases, the other decreases.
However, increases in N cause both to decrease, since sampling error is reduced.
A small sample size might lead to frequent Type II errors, i.e. it could be that your (alternative) hypotheses are right, but because your sample is so small, you fail to reject the null even though you should.
Jim have a dollar in 20 cent in his pocket and takes out a dollar how much he have left in his pocket answer- 20 cent
Answer:
critical value = 5.29
Step-by-step explanation:
Given that they are divided into 4 groups and a sample of 5 test was selected
N = 5 * 4 = 20
k = 4
∝ = 0.01
Df for numerator ( SS group )= k - 1 = 3
Df for denominator ( SSE group ) = N - k = 20 - 4 = 16
DF ( degree of freedom )
Next we will use the F table to determine the critical value
Critical value = 
= 5.29
Answer:
The mean would be 14.4 hours.
Step-by-step explanation:
In order to find the mean, or average, of the numbers, you would add all the numbers together.
17 + 15 +14 + 14 + 12 which equals 72
Then, you take the total which is 72, and divide it by how many numbers you added together which is 5.
72/5 = 14.4
