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kherson [118]
3 years ago
14

Y=−6x

Mathematics
2 answers:
White raven [17]3 years ago
8 0

Answer:

well, im not sure because what does y or x equal?

Alecsey [184]3 years ago
4 0
Answer: 0

There is no solution to the problem.
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Select the correct answer.
ad-work [718]

Answer:

A' (-1, 2)

Step-by-step explanation:

(x, y) -> (-y, x)

A' (-1, 2)

B' (1, -2)

C' (2, -2)

D' (0, -2)

3 0
3 years ago
Arthur starts his first workout routine by doing 10 push-ups. Each workout after the first, he plans to do 2 more push-ups than
Reptile [31]

Answer:

50

Step-by-step explanation:

10 + (20x2) = 50

4 0
3 years ago
Trigonometry word problems
astraxan [27]

From a point on the ground 47 feet from the foot of a tree, the angle of elevation of the top of the tree is 35º. Find the height of the tree to the nearest foot.
7 0
3 years ago
If 2x+y=8 and x-1=y then what is y? Please be detailed I want to know more then just the answer but how to solve
IgorLugansk [536]
This is Bridge Algebra 2 stuff. Well you see that 2x+y=8 and x-1=y. To slove for y you have to slove for x first to find y. So 2x+x-1=8 ( the reason I did that is because there is a y in that equation and I placed it on that equation) now lets slove this equation for x. So 3x-1=8( I add 2x with x) 3x=9 ( I made -1 a positive one and add it to 8) x=3 ( I divided 9/3 to get 3). Now that you have slove x we will use x to slove for y. So 3-1=y, 2=y. Your answer is y=2.
4 0
3 years ago
A piece of wire 11 m long is cut into two pieces. One piece is bent into a square and the other is bent into an equilateral tria
forsale [732]

Answer:

11 meters

Step-by-step explanation:

First, we can say that the square has a side length of x. The perimeter of the square is 4x, and that is how much wire goes into the square. To maximize the area, we should use all the wire possible, so the remaining wire goes into the triangle, or (11-4x).

The area of the square is x², and the area of an equilateral triangle with side length a is (√3/4)a². Next, 11-4x is equal to the perimeter of the triangle, and since it is equilateral, each side has (11-4x)/3 length. Plugging that in for a, we get the area of the equilateral triangle is

(√3/4)((11-4x)/3)²

= (√3/4)(11/3 - 4x/3)²

= (√3/4)(121/9  - 88x/9 + 16x²/9)

= (16√3/36)x² - (88√3/36)x + (121√3/36)

The total area is then

(16√3/36)x² - (88√3/36)x + (121√3/36) + x²

= (16√3/36 + 1)x² -  (88√3/36)x + (121√3/36)

Because the coefficient for x² is positive, the parabola would open up and the derivative of the parabola would be the local minimum. Therefore, to find the maximum area, we need to go to the absolute minimum/maximum points of x (x=0 or x=2.75)

When x=0, each side of the triangle is 11/3 meters long and its area is

(√3/4)a² ≈ 5.82

When x=2.75, each side of the square is 2.75 meters long and its area is

2.75² = 7.5625

Therefore, a maximum is reached when x=2.75, or the wire used for the square is 2.75 * 4 = 11 meters

3 0
3 years ago
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