H=(√3)*a/2 = 41.2
So, a=2*41.2/√3=47.6
A in how many ways can four people be selected from this group of eleven?
Step-by-step explanation:
(1 point)
No, there isn't a more efficient way to solve this system.
Yes, a more efficient way is to multiply the first equation by 4, add to eliminate y, then solve for x.
Yes, a more efficient way is to multiply the first equation by −4, add to eliminate y, then solve for x.
Yes, a more efficient way is to multiply the first equation by −4, add to eliminate x, then solve for y.
Answer:
5, 25, 109
Step-by-step explanation:
5, 25, 109, 2725 divided by 5, 5, 109, gives no remainder. They are integers and prime numbers of 2725, they are also called composite number.
