Answer:
I gues s it s yes. if correct brainlest answer pla..
If you observe the two given equations, the left hand side of both equation is the same and is equal to y.
Since the left hand side of two equations is the same, we can conclude that the right hand side of two equations must also be the same.
So, setting them right hand sides of both equations equal to each other and solving for x, we can find the solution to the simultaneous equations.
Therefore, the correct answer is option B
Answer:
21 / 143
Step-by-step explanation:
Given that:
Number of Eastern conference reps = 8
Number of western conference rep = 7
Probability of selecting 3 from Eastern reps and 2 from western reps
Probability = required outcome / Total possible outcomes
Total possible outcomes:
selection to be made = 3+ 2 = 5
Total Number of players = 8 +7 = 15
Total possible outcomes
Using combination formula :
nCr = n! / (n-r)!r!
15C5 = 15! / 10!5! = (15 * 14 * 13 * 12 * 11) / (5*4'3*2*1) = 360360 / 120 = 3003
Total possible outcomes = 3003
Required outcome :
8C3 * 7C2
8C3 = 56 ; 7C2 = 21
8C3 * 7C2 = 56 * 21 = 1176
required outcome / Total possible outcomes
= 1176 / 3003
= 21 / 143