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4 years ago

Idk what’s a true dilation

Mathematics

1 answer:

SpyIntel [72]4 years ago

5 0

A dilation is an image which has the same shape but a different size as the pre-image.

Its C:- Corresponding sides are not congruent

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A line passes through the points (1, –6) and (4, 3).

Marina CMI [18]

Answer:

y = 3x - 9

Step-by-step explanation:

We first need to find the slope (m)

m = $\frac{y_2-y_1}{x_2-x_1}$ = $\frac{3 - (-6)}{4-1}$ = $\frac{9}{3}$ = 3

y = mx + b

y = 3x + b

(4, 3)

y = 3x + b

3 = 3(4) + b

3 = 12 + b

-12 -12

-9 = b

(1, –6)

y = 3x + b

-6 = 3(1) + b

-6 = 3 + b

-3 -3

-9 = b

y = 3x - 9

To check: (1, –6)

y = 3x - 9

-6 = 3(1) - 9

-6 = 3 - 9

-6 = -6

Hope this helps!

6 0

2 years ago

Ayo can yall help me plzzz

yan [13]

Answer:

D, Impossible

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Easy Question pls help. (Algebra II type problems)

Roman55 [17]

Answer:

$\large\boxed{if\ x\neq-3\ \wedge\ y\neq0\ \wedge\ x\neq y\ \wedge\ x\neq -y}$

second

$\large\boxed{y\neq0\ \wedge\ x\neq-y\ (y\neq-x)}$

Step-by-step explanation:

We know that dividing by 0 is impossible.

Therefore, the denominator of the expression must be different from 0.

$\text{For}\\\\\dfrac{(x-y)^2}{2xy+6y}\times\dfrac{4x+12}{x^2-y^2}\\\\\\2xy+6y\neq0\qquad(1)\\\\x^2-y^2\neq0\qquad(2)$

$(1)\\2xy+6y\neq0\qquad\text{distribute}\\\\2y(x+3)\neq0\iff2y\neq0\ \wedge\ x+3\neq0\\\\2y\neq0\qquad\text{divide both sides by 2}\\\boxed{y\neq0}\\\\x+3\neq0\qquad\text{subtract 3 from both sides}\\\boxed{x\neq-3}\\==========================\\(2)\\x^2-y^2\neq0\qquad\text{use}\ a^2-b^2=(a-b)(a+b)\\(x-y)(x+y)\neq0\iff x-y\neq0\ \wedge\ x+y\neq0\\\boxed{x\neq y}\ \wedge\ \boxed{x\neq-y}$