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PolarNik [594]
2 years ago
13

Find the slope of the line through each pair of point

Mathematics
1 answer:
Stolb23 [73]2 years ago
7 0

Answer:

what are the pair of points?

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Please help me solve this question. Will make you the
zmey [24]

The relation you have shown is not a function.

In order to be a function, a relation's domain must be continuous in that no x-value is not repeated in any of the points. Since the first two points of the relation are (5,1) and (5,3), you can see that they have the same x-value, meaning that this is not a function.

One quick way you could test this is to quickly sketch a graph and use the vertical line test to see if the relation in question is a function. If it cross the vertical line once in all places, it is a function - if it crosses the vertical line more than once in any place, it is not a function.

6 0
3 years ago
Find the circumference of these circles
EastWind [94]
Formula for Circumference is 2*Pi*radius


1. 18.84 in.
2. 56.52 cm
3. 4.71 ft
4. 25.12 m
5. 37.68 ft.
6. 12.56 yd.
7.  43.96 in
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4 0
3 years ago
Find the square roots of 9604​
OLEGan [10]

Answer:

98

You have to use prime factor decompisition. I hope this helps

5 0
3 years ago
Read 2 more answers
Multiply or divide as indicated. <br><br> x 2 • x 5
WARRIOR [948]
Hi there!

{x}^{2}  \times  {x}^{5}  = x {}^{2 + 5}  =  {x}^{7}

We can also write is out entirely.
{x}^{2}  = x \times x
{x}^{5}  = x \times x \times x \times x \times x
{x}^{2}  \times  {x}^{5}  = \\  (x \times x ) \times (x \times x \times x \times x \times x) =  \\ x \times x \times x \times x \times x \times x \times x =  \\  {x}^{7}
6 0
3 years ago
A is used when the owner is still alive.
olga nikolaevna [1]

Answer:

Yes, and?

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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