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1 year ago

Find the slope of the line through each pair of point

Mathematics

1 answer:

Stolb23 [73]1 year ago

7 0

Answer:

what are the pair of points?

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PLS HELPPP IT'S ABOUT LOCUS

Ket [755]

Answer:

Here,

First Find distance between them by using formula √+x2-x1)2+(y2-y1)2

Then use the equation and then find locus.

4 0

1 year ago

What is the measure of angle A?

NikAS [45]

Answer:

Step-by-step explanation:

in a quadrilateral that's inscribed in a circle, opposite angles are supplementary.

102+78=180

3 0

2 years ago

I need help pls thank you and I'll send better pics

kakasveta [241]

$\begin{gathered} c)\text{ output = (input}\times\text{ input) }+\text{ 1} \\ d)\text{ output = input + 5} \end{gathered}$

Explanation:

$\begin{gathered} c)\text{ Change in input = 4 - 3 , 3 - 2, 2 -1 } \\ \text{change in input = 1 (it is constant )} \\ \text{The output depends on the input.} \end{gathered}$ $\begin{gathered} To\text{ get output 2: (1 }\times1\text{ )+ 1 = 1 +1 = 2} \\ To\text{ get output 5: (2}\times2)\text{ + 1 = 4 + 1 = 5} \\ To\text{ get output 10: (3}\times3)\text{ + 1 = 9 + 1 = 10} \\ To\text{ get output 17: (4}\times4)\text{ + 1 = 16 + 1 = 17} \\ To\text{ get output 26: (5}\times5)\text{ + 1 = 25 + 1 = 26} \end{gathered}$ $\begin{gathered} \text{Formula for the Process = (input}\times\text{ input) }+\text{ 1} \\ Process=(input)^2\text{ }+\text{ 1} \\ \text{output = (input}\times\text{ input) }+\text{ 1} \end{gathered}$

$\begin{gathered} d)\text{ rate of change = }\frac{change\text{ in output }}{\text{change in input}} \\ \text{rate of change = }\frac{-5-(-15)}{0-(-2)}\text{ = }\frac{10-(-5)}{3-0}\text{ = }\frac{15-10}{4-3} \\ \text{rate of change = }\frac{10}{2}\text{ = }\frac{15}{3}=\frac{5}{1} \\ \text{rate of change = 5} \end{gathered}$ $\text{output = input + 5}$

5 0

4 months ago

Consider the function f(x)= 1-|x-1|+|x+1| for -3<x<3. Recall that the absolute function can be represented as a piece wise

Kruka [31]

By the definition for the absolute value,

$|x-1|=\begin{cases}x-1&\text{for }x\ge1\\-(x-1)&\text{for }x$
$|x+1|=\begin{cases}x+1&\text{for }x\ge-1\\-(x+1)&\text{for }x$

So for the compound function $f(x)=1-|x-1|+|x+1|$ , there are three intervals to consider. What happens when $x$ ? when $-1\le x$ ? when $x\ge1$ ?

You have

$f(x)=\begin{cases}1-(-(x-1))+(-(x+1))=-1&\text{for }x$

8 0

3 years ago

What do all the points measure do it one by one ex: Point a measures,point b measures,Point C measures,Point D measures

gogolik [260]

Answer:

A=0.5 inch

B=2.25 inches

C=3.75 inches

D=5 inches

6 0

2 years ago