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2 years ago

Can some one please answer this for me? I will put their answer on brainleast

Mathematics

1 answer:

Marat540 [252]2 years ago

6 0

There is nothing to answer. I think you forgot to add the pic

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The Johnson family want to start a college fund for their daughter Gabriella. They put $63, 000 in to an account that grows at a

marissa [1.9K]

Answer:

34.13 years

Step-by-step explanation:

<u>Given formula:</u>

G(t)= 63000(1 + 0.0255/4)^4t

<u>Need to find the value of t when G(t) = 150000</u>

150000 = 63000( 1+ 0.0255/4)^4t
( 1+ 0.0255/4)^4t = 150000/63000
( 1+ 0.0255/4)^4t = 2.3809
4t* log( 1+ 0.0255/4) = log 2.3809
4t *0.00275983965 = 0.37674115501
t = 0.37674115501/(4*0.00275983965)
t = 34.13 years rounded

6 0

3 years ago

Thehhe hey!!! You guys think u guys can help me on this? :)))

Tamiku [17]

Answer:

I got 4 3/8

Step-by-step explanation:

2 1/4=2 2/8

2 2/8 + 2 1/8 =4 3/8

6 0

3 years ago

Write each as a decimal.Round to the thousands place

max2010maxim [7]

Answer:

2) 0.3

4) 0.09

6) 0.65

8) 4.45

Step-by-step explanation:

hope this helps ;)

7 0

3 years ago

Read 2 more answers

Evaluate the expression. 0.1×( – 0.9+ – 0.2÷ – 0.5) Write your answer as an integer or a decimal. Do not round.

matrenka [14]

Answer:

-0.05

Step-by-step explanation:

Given the expression :

0.1×( – 0.9+ – 0.2÷ – 0.5)

Evaluating the bracket :

0.1 * (-0.9 - 0.2 ÷ - 0.5)

Solving the division first

-0.2 ÷ - 0.5 = 0.4

Now we have ;

0.1 * (-0.9 + 0.4)

0.1 * - 0.5

= - 0.05

4 0

3 years ago

If y=(x^2-4)^5(3x+4)^4

alexira [117]

Answer:

$y'=2(3x+4)^3(x^2-4)^4(21x^2+20x-24)$

Step-by-step explanation:

$y=(x^2-4)^5(3x+4)^4$

$y'=[\frac{d}{dx}(x^2-4)^5](3x+4)^4+(x^2-4)^5[\frac{d}{dx}(3x+4)^4]$

$y'=10x(x^2-4)^4(3x+4)^4+(x^2-4)^5(12(3x+4)^3)$

$y'=10x(x^2-4)^4(3x+4)^4+12(x^2-4)^5(3x+4)^3$

$y'=2(3x+4)^3(x^2-4)^4(21x^2+20x-24)$

5 0

2 years ago