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Gemiola [76]
3 years ago
11

Jeff had 8 dogs he ate 1 how many left?

Mathematics
2 answers:
Nataly [62]3 years ago
5 0

Answer:

7

Step-by-step explanation:

thats kinda sus but 8-1

ch4aika [34]3 years ago
3 0

Answer:

7

Step-by-step explanation:

8-1=7

why would he eat his dogs though

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3 years ago
Brendan's dog has a mass of 25,700 grams. What is the dog's mass in milligrams? Show your work.
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25700000

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4 years ago
What sequence starts with 1 and has a common difference of 2
olga2289 [7]

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3 years ago
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3 0
3 years ago
?????????????????????????????
Angelina_Jolie [31]

Answer:

Length of the training track running around the field =524.38\ meters

Step-by-step explanation:

Length of the training track = Outer boundary measures Or Circumference of the field.

We have a rectangular enclosure and circumference/perimeter of a rectangle =2(length+Width)

And we have2 semicircle of same measures,2 semicircles of same measure can be considered as a full circle.

So circumference of a circle =2\pi (r)\ Or\ \pi (d) where r is the radius and d is the diameter.

And we see we have already being given the values of length ,width but nowhere it has mentioned the diameter.

But from the figure if we look upon,the width of the rectangle is the diameter of the semicircle,so diameter of the circle which is (d) = 67\ m

Finally the training track length = Perimeter of rectangle + Circumference of the circle,which

=2(length+width) + \pi (diameter)

=2(90+67) +3.14(67)

=(314+210.38) = 524.38\ m

So the length of the training track 524.38 in meters.

The units are in meters.

3 0
3 years ago
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