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sweet [91]
3 years ago
7

Pleaseeee helppp meeee

Mathematics
1 answer:
balandron [24]3 years ago
5 0
Parrelel why is yes help me pro
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Simplify the expression below! The picture is down below!
n200080 [17]

Answer:

Its C

Step-by-step explanation:

3 0
3 years ago
Help, I need it fast! D:
patriot [66]
Let's solve this problem step-by-step.

STEP-BY-STEP SOLUTION:

Let's first establish the simple interest formula which we will require to solve this problem as displayed below:

Simple Interest = Principal × Rate of Interest × No. of Time Periods

I = PRN

Now let's substitute the values from the problem into this formula as displayed below:

I = $90

P = ?

R = 6%

N = 3 years

I = PRN

90 = P × 0.06 × 3

P = 90 / 0.06 × 3

P = 90 / 0.18

P = $500

ANSWER:

As the principal and the amount borrowed is the same, Claire borrowed $500. Therefore, the answer is:

D ) $500

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5 0
3 years ago
Find the value of (1.52 x 〖10〗^5) + (5.4 x 〖10〗^4)
Bogdan [553]

Answer:three significant figures: the 4, the 1, and the 8. This is ... 3) 7.09 x 10¯5 - three significant figures. ... Here is how it would be written: 9.160 x 104. ... Find the number with the LEAST number of digits in the decimal portion. ... The first value in the problem, with three significant places to the right of the decimal point, ...

Missing: (5.4 ‎| Must include: (5.4

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
For every 6 students who purchase a bag of M&amp;M’s, there are 5 students who purchase a pack of gum. Use M for the number of s
Assoli18 [71]

Answer:

  M/6 = G/5

Step-by-step explanation:

We are given a relation between the numbers of students in two different groups. That relation can be used to write an equation.

<h3>Groups who bought M&Ms</h3>

If we consider M&M buyers to be 6 in a group, then the number of those groups is ...

  M/6

<h3>Groups who bought gum</h3>

Similarly, the number of groups who bought gum will be ...

  G/5

where there are 5 gum-buyers in each group.

<h3>Equation</h3>

The problem statement tells us that for each group of one kind, there is a matching group of the other kind. That is, the numbers of groups are equal:

  M/6 = G/5

4 0
2 years ago
The value of 2 in 204.75 is how many times in the value of the 2 in 103.52
SOVA2 [1]
10000 times the value of the other one

5 0
3 years ago
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