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Yuki888 [10]
2 years ago
6

Helppppppppppppppppppppppppppppppppppppp

Mathematics
2 answers:
sineoko [7]2 years ago
7 0

Answer:

no solution

Step-by-step explanation:

irinina [24]2 years ago
5 0

Answer: n = n∈∅, n∈∅ stands for no solutions.

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a survey indicated that 5 out of 8 doctors used brand X aspirin. If 4000 doctors were surveyed, how many used brand X?
fredd [130]

Answer:

2500 doctors

Step-by-step explanation:

4000/8= 500

500x5=2500

8 0
4 years ago
What is the sum of <br> 1<br> 8<br> +<br> 5<br> 16<br> +<br> 3<br> 8<br> ?
Alexus [3.1K]

Answer:

41

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Prove that sinxtanx=1/cosx - cosx
maks197457 [2]

Answer:

See below

Step-by-step explanation:

We want to prove that

\sin(x)\tan(x) = \dfrac{1}{\cos(x)} - \cos(x), \forall x \in\mathbb{R}

Taking the RHS, note

\dfrac{1}{\cos(x)} - \cos(x) = \dfrac{1}{\cos(x)} - \dfrac{\cos(x) \cos(x)}{\cos(x)} = \dfrac{1-\cos^2(x)}{\cos(x)}

Remember that

\sin^2(x) + \cos^2(x) =1 \implies 1- \cos^2(x) =\sin^2(x)

Therefore,

\dfrac{1-\cos^2(x)}{\cos(x)} = \dfrac{\sin^2(x)}{\cos(x)} = \dfrac{\sin(x)\sin(x)}{\cos(x)}

Once

\dfrac{\sin(x)}{\cos(x)} = \tan(x)

Then,

\dfrac{\sin(x)\sin(x)}{\cos(x)} = \sin(x)\tan(x)

Hence, it is proved

5 0
3 years ago
WHAT IS THE RATE OF CHANGE FOR THIS
stealth61 [152]
Well first find 2 points, I am going to choose (0,0.5) and (1,0.3). So to find rate of change or Slope it is y2-y1/x2-x1 so we are doing that, .3-.5/1-0. which will be -.2/1

Your answer: -.2/1
4 0
3 years ago
What does x equal if the equation is x+2.62=6.37
KengaRu [80]

Answer:

x=3.75

The drawing will help

5 0
3 years ago
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