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2 years ago

Helppppppppppppppppppppppppppppppppppppp

Mathematics

2 answers:

sineoko [7]2 years ago

7 0

Answer:

no solution

Step-by-step explanation:

irinina [24]2 years ago

5 0

Answer: n = n∈∅, n∈∅ stands for no solutions.

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6th grade math! Help me please :))

lara31 [8.8K]

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2 years ago

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Cecily’s teacher held a raffle. To win the raffle, a student has to pick a paper scroll with an integer written on it. The chart

Luda [366]

Answer:

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3 years ago

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A=1/2 (a+b)h work out A if a=2 b=7 h=3

BartSMP [9]

Step-by-step explanation:

A =1/2(a+b)h

1/2(2+7)3
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hope it helps.

6 0

2 years ago

Shanley would like to give $5 gift cards

Serjik [45]

Answer:

$5x + $4y ≤ $120

let x = 10

y = 5

$70 ≤ 120

Step-by-step explanation:

Note that

> means greater than

< means less than

≥ means greater or equal to

≤ means less than or equal to

the total amount Shanley has is $120. She can spend less than this amount or the amount exactly. So, the inequality sign to be used is ≤

$5x + $4y ≤ $120

let x = 10

y = 5

(50) + 20 ≤ 120

$70 ≤ 120

4 0

3 years ago

How do u factor this

PilotLPTM [1.2K]

You can factor a parabola by finding its roots: if

$p(x)=x^2+bx+c$

has roots $x_1,\ x_2$ , then you have the following factorization:

$p(x) = (x-x_1)(x-x_2)$

In order to find the roots, you can use the usual formula

$x_{1,2} = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

In the first example, this formula leads to

$x_{1,2} = \dfrac{-2\pm\sqrt{4+4}}{2} = \dfrac{-2\pm\sqrt{8}}{2} = \dfrac{-2\pm2\sqrt{2}}{2} = 1 \pm \sqrt{2}$

So, you can factor

$x^2-2x-1 = (x-1-\sqrt{2})(x-1+\sqrt{2})$

The same goes for the second parabola.

As for the third exercise, simply plug the values asking

$f(1.5)=-5.25$

you get

$f(-1.5) = 1.5c-3 = -5.25$

Add 3 to both sides:

$1.5c = -2.25$

Divide both sides by 1.5:

$c = 1.5$

7 0

3 years ago