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nekit [7.7K]
3 years ago
8

determine if the given function x = cos 2t is a solution to the given differential equation dx/dt + tx = sin 2t.

SAT
1 answer:
levacccp [35]3 years ago
4 0

Answer:

n

Explanation:

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Use the information above and the trigonometric identities to prove that Asin(wt
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Using sum and difference identities from trigonometric identities shows that; Asin(ωt)cos(φ) +Acos(ωt)sin(φ) =  Asin(ωt + φ)

<h3>How to prove Trigonometric Identities?</h3>

We know from sum and difference identities that;

sin (α + β) = sin(α)cos(β) + cos(α)sin(β)

sin (α - β) = sin(α)cos(β) - cos(α)sin(β)

c₂ = Acos(φ)

c₁ = Asin(φ)

The Pythagorean identity can be invoked to simplify the sum of squares:

c₁² + c₂² =

(Asin(φ))² + (Acos(φ))²

= A²(sin(φ)² +cos(φ)²)

= A² * 1

= A²

Using common factor as shown in the trigonometric identity above for Asin(ωt)cos(φ) +Acos(ωt)sin(φ) gives us;  Asin(ωt + φ)

Complete Question is;

y(t) = distance of weight from equilibrium position

ω = Angular Frequency (measured in radians per second)

A = Amplitude

φ = Phase shift

c₂ = Acos(φ)

c₁ = Asin(φ)

Use the information above and the trigonometric identities to prove that

Asin(ωt + φ) = Asin(ωt)cos(φ) +Acos(ωt)sin(φ)

Read more about Trigonometric Identities at; brainly.com/question/7331447

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Read the excerpt from "the catch. " as rohan, the youngest of the elf competitors arrived at the eastern foothills where the fel
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He wants Rohan to concentrate on the race.

Explanation:

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A fair six-sided die, with sides numbered 1 through 6, will be rolled a total of 15 times. Let x¯1 represent the average of the
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The sampling distribution of the difference in sample means x⁻₁ - x⁻₂ is; 3.5 - 3.5 = 0

<h3>Difference in sample means</h3>

We are told that;

  • A fair six-sided die, with sides numbered 1 through 6, will be rolled a total of 15 times.
  • x⁻₁ represents the average of the first ten rolls.
  • x⁻₂ represents the average of the remaining five rolls.

Now, the average of the largest and lowest numbers of the six sided die is;

E(x) = (6 + 1)/2 = 3.5

Thus, the average mean of the first ten rows is expressed as;

E(x⁻₁) = (n * E(x))/n

E(x⁻₁) = (10 * 3.5)/10

E(x⁻₁) = 3.5

The average mean of the last five rolls will be;

E(x⁻₂) = (n * E(x))/n

E(x⁻₂) = (5 * 3.5)/5

E(x⁻₂) = 3.5

Thus;

x⁻₁ - x⁻₂ = 3.5 - 3.5 = 0

Read more about difference in sample means at; brainly.com/question/16428987

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Click this link to view O*NET's Skills section for Air Traffic Controllers. Note that common skills are listed toward the top, a
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Explanation:

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