What is the answer ????

A user’s laptop hard drive contains sensitive information. The user often plugs the laptop into the corporate network. A sensiti

jekas [21]

Answer:

the user should disable file and print sharing on the laptop

Explanation:

According to my research on information technology and cyber security, I can say that based on the information provided within the question in order to prevent this the user should disable file and print sharing on the laptop. This is because this file and printer sharing allows users to see your files that you have available as shared and copy or print those files. Which if they are sensitive data you should just disable this option so that people on the same network cannot see or access these files.

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

6 0

3 years ago

1. Implement a method factorial(int n), that takes a number (int) and returns its factorial. Factorial of an integer is the prod

marysya [2.9K]

Answer:

import java.io.*;

import java.util.*;

public class Main

{

public static int factorial(int n){

if (n == 0)

return 1;

else

return(n * factorial(n-1)); //recursively calling factorial function

}

public static void fibbonaci(int n)

{

if(n>0)

{

c=a+b; //next term in series

a=b;

b=c;

System.out.print(" "+c);

fibbonaci(n-1); //recursively calling fibbonaci function

}

static int a=0,b=1,c;

public static void main(String[] args) {

int list_num,fact;

List<Integer> num=Arrays.asList(1,3,5,7,9); //arraylist with 1,3,5,7,9

for(Integer i:num) //for-each loop

{

a=0;

b=1;

list_num=i.intValue();

System.out.println("Fibbonaci series for "+list_num);

System.out.print(a+" "+b);

fibbonaci(list_num-2); //calling fibbonaci for values in list

fact=factorial(list_num); //calling factorial for values in list

System.out.println();

System.out.println("Factorial for "+list_num+" is "+fact);

System.out.println();

}

6 0

3 years ago

What web 2.0 features allows users to subscribe to a data plan that charges for the amount of time spent on the internet?

galina1969 [7]

Answer:

The answer to this question is given in the explanation section. The correct option is long tail

Explanation:

a.Folksonomy

Folksonomy is a way of organizing data and digital content. With Web 2.0, users can collaboratively manage and tag photos, journals and other media. As more users do this, creates a system of classification for the media and information. so this option is not correct

b. long tail (correct option)

Some sites are able to offer services as well in which users can subscribe monthly or pay a fee every so often. An example of this would be Netflix.

c.user participation

All users have the free will to contribute to the site which makes many Web 2.0 pages public. With sites such as Wikipedia, anyone is open to the editing of articles. Information is provided two-way instead of solely from the site owner.

d.application

Web 2.0 applications that allow anyone to create and share online information or material they have created. As you know that there are number of different types of web 2.0 applications including wikis, blogs, social networking, folksonomies, podcasting & content hosting services.

3 0

3 years ago

Write a program in Java programming language to display or calculate “Hello, Daddy and Mum”

olganol [36]

Answer:

class Simple{

public static void main(String args[]){

System.out.println("Hello Daddy and Mum);

}

Explanation:

First, we create a class, then a method and then give the Integrated Data Environment (IDE) the command to give out an output that says Hello, Daddy and Mum”

8 0

2 years ago

Computer Networks - Queues

lyudmila [28]

Answer:

the average arrival rate \lambda in units of packets/second is 15.24 kbps

the average number of packets w waiting to be serviced in the buffer is 762 bits

Explanation:

Given that:

A single channel with a capacity of 64 kbps.

Average packet waiting time $T_w$ in the buffer = 0.05 second

Average number of packets in residence = 1 packet

Average packet length r = 1000 bits

What are the average arrival rate \lambda in units of packets/second and the average number of packets w waiting to be serviced in the buffer?

The Conservation of Time and Messages ;

E(R) = E(W) + ρ

r = w + ρ

Using Little law ;

r = λ × T_r

w = λ × T_w

r / λ = w / λ + ρ / λ

T_r =T_w + 1 / μ

T_r = T_w +T_s

where ;

ρ = utilisation fraction of time facility

r = mean number of item in the system waiting to be served

w = mean number of packet waiting to be served

λ = mean number of arrival per second

T_r =mean time an item spent in the system

T_w = mean waiting time

μ = traffic intensity

T_s = mean service time for each arrival

the average arrival rate \lambda in units of packets/second; we have the following.

First let's determine the serving time T_s

the serving time T_s $= \dfrac{1000}{64*1000}$

= 0.015625

now; the mean time an item spent in the system T_r = T_w +T_s

where;

T_w = 0.05 (i.e the average packet waiting time)

T_s = 0.015625

T_r = 0.05 + 0.015625

T_r = 0.065625

However; the mean number of arrival per second λ is;

r = λ × T_r

λ = r / T_r

λ = 1000 / 0.065625

λ = 15238.09524 bps

λ ≅ 15.24 kbps

Thus; the average arrival rate \lambda in units of packets/second is 15.24 kbps

b) Determine the average number of packets w waiting to be serviced in the buffer.

mean number of packets w waiting to be served is calculated using the formula

w = λ × T_w

where;

T_w = 0.05

w = 15238.09524 × 0.05

w = 761.904762

w ≅ 762 bits

Thus; the average number of packets w waiting to be serviced in the buffer is 762 bits

4 0

3 years ago

What is the answer ????​

What is the answer ????