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jolli1 [7]
2 years ago
14

A angle is measured in​

Mathematics
1 answer:
Viefleur [7K]2 years ago
3 0
Angles are measured in degree’s, the symbol for degree’s is a little circle (x °)
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Lara went to the nursery and spent $140 she purchased 4 plants each of the plant costs the same price what is the cost of 1 plan
trapecia [35]

Answer:

$35 per plant

Step-by-step explanation:

You take the 140 and divide that by 4 to get your answer.

8 0
3 years ago
Please solve this <br><br> 4 3/4 * 7 2/17<br><br> A. 28<br><br> B. 32<br><br> C. 35<br><br> D. 40
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The answer is B. 32
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X^2 + y^2=40 and y=x-4 solve this simultaneous equation
inn [45]
Write x-4 instead of y.
x²+(x-4)²=40
x²+x²-8x+16=40
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(x-6)(x+2)=0
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3 0
3 years ago
8 is what percent of 2500
Nataly [62]
8 percent of 2500 is 200.
5 0
3 years ago
Read 2 more answers
A researcher wishes to estimate the average blood alcohol concentration​ (BAC) for drivers involved in fatal accidents who are f
Mnenie [13.5K]

Answer:

A 90% confidence interval for the mean BAC in fatal crashes in which the driver had a positive BAC is [0.143, 0.177] .

Step-by-step explanation:

We are given that a researcher randomly selects records from 60 such drivers in 2009 and determines the sample mean BAC to be 0.16 g/dL with a standard deviation of 0.080 ​g/dL.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                               P.Q.  =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~   t_n_-_1

where, \bar X = sample mean BAC = 0.16 g/dL

            s = sample standard deviation = 0.080 ​g/dL

            n = sample of drivers = 60

            \mu = population mean BAC in fatal crashes

<em>Here for constructing a 90% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation. </em>

So, a 90% confidence interval for the population mean, \mu is;

P(-1.672 < t_5_9 < 1.672) = 0.90  {As the critical value of t at 59 degrees of

                                              freedom are -1.672 & 1.672 with P = 5%}    P(-1.672 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 1.672) = 0.90

P( -1.672 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 1.672 \times {\frac{s}{\sqrt{n} } } ) = 0.90

P( \bar X-1.672 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+1.672 \times {\frac{s}{\sqrt{n} } } ) = 0.90

<u>90% confidence interval for</u> \mu = [ \bar X-1.672 \times {\frac{s}{\sqrt{n} } } , \bar X+1.672 \times {\frac{s}{\sqrt{n} } } ]

                                       = [ 0.16-1.672 \times {\frac{0.08}{\sqrt{60} } } , 0.16+1.672 \times {\frac{0.08}{\sqrt{60} } } ]

                                       = [0.143, 0.177]

Therefore, a 90% confidence interval for the mean BAC in fatal crashes in which the driver had a positive BAC is [0.143, 0.177] .

7 0
3 years ago
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