First of all, as I told you a little while ago, here is the formula
that solves ALL probability problems. Memorize this:
Probability =
(number of different successful possibilities)
divided by
(total number of all possibilities).
There are 10 keys in the bag. The total number of possible results
of pulling out one key out is 10.
3 of the keys start the car. The other 7 keys don't.
What are the 'successful' possibilities ?
The question asks for the probability of pulling keys that DON'T work.
So for this particular calculation, we're talking about choosing keys
that DON'T work. There are 7 of those.
The probability of drawing a key that doesn't work the first time is 7/10 .
Since the first key is put back in the bag and the bag is mixed, the
situation on the second draw is exactly the same as on the first one.
Thje probability of drawing a key that doesn't work the second time is 7/10 .
The probability of both events happening is (7/10)x(7/10) = 49/100 = 49% .
Answer:
The correct answer is D) 7+(3+1)=(7+3)+1
Step-by-step explanation:
The associative property of addition states that it doesn't matter how you group numbers inside of parenthesis, it gives you the same answer. So even though the groupings are different in that example, the answer is still the same.
Answer:
P(t) = 19t - 1900
Step-by-step explanation:
The factory expenses = $1900
Per toy expense = $11
The selling price of toy = $30
Now we have to convert it in the equation form. Use the below formula to convert these values in equation form.
Profit = Total revenue – total cost
Profit = TR – (variable cost + fixed cost)
Profit on truck = 30t – (11t + 1900)
Profit = 30t – 11t – 1900
P(t) = 19t - 1900
answer :
( 1, 1 / 2 )
explanation :
<em>Midpoint formula : </em>
<em>(x^1, y^1) , (x^2, y^2)</em>
<em></em>
<em>M = ( x^1 + x^2 / 2 ), ( y^1 + y^2 / 2 ). </em>
<em></em>
<em>(x^1, y^1) = (4, 3/4), (x^2, y^2) = (-2, 1/4). </em>
<em></em>
<em>= ( -2 + 4 / 2, 1/4 + 3/4 / 2 ) </em>
<em></em>
<em>= ( 1, 1 / 2 ) </em>