The probabilities are given below:
- The probability that the first son is normal is 1/4
- probability first daughter is normal = 1/2
- Probability = 1/4
<h3>How to solve for the probability</h3>
For females we have the following data
50% = normal, 50% = carriers; 100%= normal vision
50% males = color blind ;50% = normal
<h3>a.The probability of having a normal first son</h3>
p(first son) = ½
Prob( normal)= ½
=½ x ½
= 1/4 0r 0.25
<h3>b . probability first daughter is normal</h3>
Probability of the first being a girl = ½
Prob(normal ) = 1
½ x 1 = 1/2
c. color blind
= 1/2 x 1/2
= 1/4
Read more on probability here:
brainly.com/question/24756209
#SPJ1
Complete question
A husband and wife have normal vision, although both of the couple's fathers are red–green color-blind, an inherited X-linked recessive condition.
A)What is the probability that the couple's first child will be a normal son? Enter your answer as a fraction
B)What is the probability that the couple's first child will be a normal daughter? Enter your answer as a fraction
What is the probability that the couple's first child will be a color-blind son?
