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3 years ago

14

Kirk is taking an exam and has 1 1/2 hours to complete the test. He has used 1/3 of his time already. How much time has Kirk use

d already on the test?

2 answers:

Crank3 years ago

5 0

Answer:

(1/2) half an hour.

Step-by-step explanation:

1 1/2 x 1/3 = 3/2 x 1/3 = 3/6 = 1/2

maks197457 [2]3 years ago

3 0

Answer:

30 minutes!!!!

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Answer: No

Step-by-step explanation:

Given: The San Diego Safari Park charges $18 for parking, and an admission fee of $56.

This can be represented by the equation c = 56p + 18, where c is the total cost and p is the number of people.

Equation of direct proportion: $k=\dfrac{y}x$

But here we have a y-intercept as 18.

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Which of the following points lies on the circle whose center is at the origin and whose radius is 13?

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any point that is on the circle will have a distance of "radius" units, namely 13 units, since the radius is just that.

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Number 8 Brainliest and 20 points

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The number of hours worked per year per person in a state is normally distributed with a standard deviation of 39. A sample of 1

evablogger [386]

Answer:

The 98% confidence interval for the population mean number of hours worked per year per person is (2146, 2193).

Step-by-step explanation:

The question is incomplete.

The number of hours registered in the sample are:

2051 2061 2162 2167 2169 2171

2180 2183 2186 2195 2196 2198

2205 2210 2211

The sample mean can be calculated as:

$M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{15}(2051+2061+2162+2167+2169+2171+2180+2183+2186+2195+2196+2198+2205+2210+2211)\\\\\\M=\dfrac{32545}{15}\\\\\\M=2169.67\\\\\\$

We have to calculate a 98% confidence interval for the mean.

The population standard deviation is know and is σ=39.

The sample mean is M=2169.67.

The sample size is N=15.

As σ is known, the standard error of the mean (σM) is calculated as:

$\sigma_M=\dfrac{\sigma}{\sqrt{N}}=\dfrac{39}{\sqrt{15}}=\dfrac{39}{3.873}=10.07$

The z-value for a 98% confidence interval is z=2.326.

The margin of error (MOE) can be calculated as:

$MOE=z\cdot \sigma_M=2.326 \cdot 10.07=23.43$

Then, the lower and upper bounds of the confidence interval are:

$LL=M-t \cdot s_M = 2169.67-23.43=2146\\\\UL=M+t \cdot s_M = 2169.67+23.43=2193$

The 98% confidence interval for the population mean is (2146, 2193).

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Answer:

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Step-by-step explanation:

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