Answer:
I do think I can answer this
21 cars, 32 motorcycles.create a system of equations using x for cars and y for motorcycles.
multiply the top equation by 2 to prepare for elimination method
subtract terms
divide both sides by negative 2 to solve for x
x =21
plug in x into original equation to solve for y.
21 + y = 53
subtract both sides by 21
y=32
28 to 42 means 28/42
We now reduce 28/42 to lowest terms.
28 ÷ 7 = 4
42 ÷ 7 = 6
We now have 4/6.
We now reduce 4/6.
4 ÷ 2 = 2
6 ÷ 2 = 3
Final answer: 2/3
<h3>Answer:</h3>
Yes, ΔPʹQʹRʹ is a reflection of ΔPQR over the x-axis
<h3>Explanation:</h3>
The problem statement tells you the transformation is ...
... (x, y) → (x, -y)
Consider the two points (0, 1) and (0, -1). These points are chosen for your consideration because their y-coordinates have opposite signs—just like the points of the transformation above. They are equidistant from the x-axis, one above, and one below. Each is a <em>reflection</em> of the other across the x-axis.
Along with translation and rotation, <em>reflection</em> is a transformation that <em>does not change any distance or angle measures</em>. (That is why these transformations are all called "rigid" transformations: the size and shape of the transformed object do not change.)
An object that has the same length and angle measures before and after transformation <em>is congruent</em> to its transformed self.
So, ... ∆P'Q'R' is a reflection of ∆PQR over the x-axis, and is congruent to ∆PQR.
