janet obtained 32% for her statistics test, which was out of a total of 300 marks. how much should she score in the computer sci
ence test that is out of 200 marks in total if she is to get proportionally weighted average of 46%
1 answer:
Her score in computer to get a proportionally weighted average of 46% will be 134.
The total score for both subjects = 200 + 300 = 500
Since the proportionally weighted average is 46%, then her score will be:
= 46% × 500
= 0.46 × 500
= 230
Since she had 32% for her statistics test, which was out of a total of 300. Her score will be:
= 32% × 300
= 0.32 × 300
= 96
Therefore, her score in computer will be:
= 230 - 96
= 134
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1/3n - 8 = -13 <== ur equation
1/3n = -13 + 8
1/3n = - 5
n = -5 * 3
n = -15
check..
1/3(-15) - 8 = -13
-5 - 8 = -13
-13 = -13 (correct)
so the number (n) = -15
Answer:
8
Step-by-step explanation:
8y-3y=40
5y. = 40
y. =8
the value of y is 8.
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