<u><em>Note: As you may have unintentionally missed to add the value choices. But, I would make sure to explain the concept so that you may improve your understanding in terms of solving these type of questions.</em></u>
Answer:
Any value other than the values 
will not be a solution of 
.
Step-by-step explanation:
Considering the equation
Steps to solve the equation
As
![\mathrm{For\:}x^3=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt[3]{f\left(a\right)},\:\sqrt[3]{f\left(a\right)}\frac{-1-\sqrt{3}i}{2},\:\sqrt[3]{f\left(a\right)}\frac{-1+\sqrt{3}i}{2}](https://tex.z-dn.net/?f=%5Cmathrm%7BFor%5C%3A%7Dx%5E3%3Df%5Cleft%28a%5Cright%29%5Cmathrm%7B%5C%3Athe%5C%3Asolutions%5C%3Aare%5C%3A%7Dx%3D%5Csqrt%5B3%5D%7Bf%5Cleft%28a%5Cright%29%7D%2C%5C%3A%5Csqrt%5B3%5D%7Bf%5Cleft%28a%5Cright%29%7D%5Cfrac%7B-1-%5Csqrt%7B3%7Di%7D%7B2%7D%2C%5C%3A%5Csqrt%5B3%5D%7Bf%5Cleft%28a%5Cright%29%7D%5Cfrac%7B-1%2B%5Csqrt%7B3%7Di%7D%7B2%7D)
![x=\sqrt[3]{\frac{1}{8}},\:x=\sqrt[3]{\frac{1}{8}}\frac{-1+\sqrt{3}i}{2},\:x=\sqrt[3]{\frac{1}{8}}\frac{-1-\sqrt{3}i}{2}](https://tex.z-dn.net/?f=x%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B1%7D%7B8%7D%7D%2C%5C%3Ax%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B1%7D%7B8%7D%7D%5Cfrac%7B-1%2B%5Csqrt%7B3%7Di%7D%7B2%7D%2C%5C%3Ax%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B1%7D%7B8%7D%7D%5Cfrac%7B-1-%5Csqrt%7B3%7Di%7D%7B2%7D)
So,
Therefore,
Any value other than the values will not be a solution of .
Keywords: solution, value
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Check the picture below.
we know the lines are angle bisectors, so the line makes twin angles, so the line FP is making twin angles, we also know the angle FZP and the angle FYP are right-angles, as well as FP is a common hypotenuse to two right triangles, thus by the HA postulate for right triangles, triangle FPZ and triangle FPY are both congruent, so their sides are also congruents, thus PY = PZ.
When you have an exponent that is negative, it means to take reciprocal of the fraction then take it the power.
Some examples:
5^-2 = 1/5^2 = 1/25
10^-3 = 1/10^-3 = 1/1000
If this answer wasn't clear enough, just comment below or DM me a message!
B= 2000 + CD
98000 = B + CD
substitute b in
98000 = 2000 + CD + CD
add variables
98000 = 2000 + 2CD
subtract 2000 from each side
96000 = 2CD
divide each side by 2
48000 = CD
