Which of the following is the final step in bisecting an angle?

Mathematics

1 answer:

Eduardwww [97]2 years ago

8 0

Answer:

Step-by-step explanation:

This link will show you an animation of the angle bisection construction.

https://www.mathsisfun.com/geometry/construct-anglebisect.html

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alexandr1967 [171]

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Ganezh [65]

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3 years ago

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Hunter-Best [27]

Let's simplify the following expression:

$\text{ }\frac{\text{ \lparen2x}^4\text{ - y}^6\text{z}^{-4})^2}{\text{ 2x}^2\text{z}^3}\text{ }\cdot\text{ }\frac{\text{ 6x}^5\text{y}^{-4}\text{z}^{-5}}{\text{ \lparen2x}^6\text{y}^3\text{z}^{-3})^2}$

We get,

$\text{ }\frac{(\text{2x}^4\text{ - y}^6\text{z}^{-4})^2}{\text{ 2x}^2\text{z}^3}\text{ }\cdot\text{ }\frac{6x^5y^{-4}z^{-5}}{(2x^6y^3z^{-3})^2}$ $\text{ }\frac{(2x^4-y^6z^{-4})^2(6x^5y^{-4}z^{-5})}{(2x^2z^3)(2x^6y^3z^{-3})^2}$ $\text{ }\frac{(4x^8\text{ - 4x}^4y^6z^{-4}\text{ + y}^{12}z^{-8})(6x^5y^{-4}z^{-5})}{(2x^2z^3)(4x^{12}y^6z^{-6})}$ $\text{ }\frac{24x^{13}y^{-4}z^{-5}\text{ - 24x}^9y^2z^{-9}\text{ + 6x}^5y^8z^{-13}}{8x^{14}y^6z^{-3}}$

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1 year ago

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patriot [66]

Answer:

I got 32.

Step-by-step explanation:

I used the Pythagorean theorem to find the lengths of the width and length. The length between (-1, 4) and (3, 3) was approximately 4 in. The distance between (-1, 4) and (-3, -4) was approximately 8 in. I then used those numbers to find the perimeter ((2*4)+(2*8))

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3 years ago

Read 3 more answers