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andriy [413]
2 years ago
11

Which of the following is the final step in bisecting an angle?

Mathematics
1 answer:
Eduardwww [97]2 years ago
8 0

Answer:

A.

Step-by-step explanation:

This link will show you an animation of the angle bisection construction.

https://www.mathsisfun.com/geometry/construct-anglebisect.html

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A={4,8,2,16,...} description of set
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ODD NUMBERS

Step-by-step explanation:

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Which expression is equal to 48 + 72?
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24 times 2 equals 48 , 24 times 3 equals 72 . Therefore it’s A
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HELP QUICK! which graph represents the solution set for the inequality PICTURE INCLUDED
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Which ordered pair (x, y) satisfies the system of equations? 1/2 x − 1/4 y = 10 1/8 x − 1/8 y = 19
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Step-by-step explanation:

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2 years ago
An object is launched at 29.4 meters per
Lerok [7]

Answer:

The reasonable domain for the scenario is option 'a';

a) [0, 7]  

Step-by-step explanation:

For the projectile motion of the object, we are given;

The speed at which the object is launched, v = 29.4 meters per second

The height of the platform from which the object is launched, h = 34.3 meter

The equation for the height of the object as a function of time 'x' is given as follows;

f(x) = -4.9·x² + 29.4·x + 34.3

The domain for the scenario, is given by the possible values of 'x' for the function, which is found as follows;

At the height from which the object is launched, x = 0, and f(x) = 34.3

At the ground level to which the object can drop, f(x) = 0

∴ f(x) = -4.9·x² + 29.4·x + 34.3 = 0

-4.9·x² + 29.4·x + 34.3 = 0

By the quadratic formula, we have;

x = (-29.4 ± √(29.4² - 4 × (-4.9) × 34.3))/(2 × (-4.9)

∴ x = -1, or 7

Given that time is a natural number, we have the reasonable domain for the scenario as the start time when the object is launched, t = 0 to the time the object reaches the ground, t = 7

Therefore, the reasonable domain for the scenario is; 0 ≤ x ≤ 7 or [0, 7].

4 0
3 years ago
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