Question

What are the zeros of the polynomial function ? f(x) = 2x (x-2) (1-x)

Answer 1

Answer:

The zeros are 0 ,2, and 1

Step-by-step explanation:

f (x) = 2x (x - 2) (1 - x)

set f(x) equal to y

y = 2x (x - 2) (1 - x)

solve when y is 0 because when y is 0 then it is an x-intercept

0 = 2x (x - 2) (1 - x)

separate all of the equations out

0 = 2x

0 = (x - 2)

0 = (1 - x)

solve for x for each equation

0 = 2x

• divide both sides by 2
• 0/2 = 0 and 2x/2 = x
• 0 = x
• x = 0

0 = (x - 2)

• add 2 to both sides
• 0 + 2 = 2 and (x - 2) + 2 = x
• 2 = x
• x = 2

0 = (1 - x)

• subtract 1 from both sides
• 0 - 1 = -1 and (1 - x) - 1 = -x
• -1 = - x
• multiply both sides by -1
• -1 · -1 = 1 and -x · -1 = x
• 1 = x
• x = 1