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Evgen [1.6K]
3 years ago
9

a1" title="\lim_{x \to 0 } \frac{x-sin(2x)}{x+sin(3x)}" alt="\lim_{x \to 0 } \frac{x-sin(2x)}{x+sin(3x)}" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
nekit [7.7K]3 years ago
5 0

Step-by-step explanation:

=  \lim \limits_{x \to0} \frac{x -  \sin(2x) }{x +  \sin(3x) }

=  \lim \limits_{x \to0} \frac{ \frac{d}{dx}(x -  \sin(2x) ) }{ \frac{d}{dx} (x +  \sin(3x) )}

=  \lim \limits_{x \to0} \frac{1 -  2\cos(2x) }{1 + 3 \cos(3x) }

=  \lim \limits_{x \to0} \frac{ \frac{d}{dx}(1 + 2 \cos(2x) ) }{ \frac{d}{dx} (1 + 3 \cos(3x) )}

=  \lim \limits_{x \to0} \frac{ - 4 \sin(2x) }{ - 9 \sin(3x) }

=  \frac{ - 4.2}{ - 9.3}

=  \frac{ - 8}{ - 27}

=  \frac{8}{27}

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Hope this helped :)

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2 years ago
Help right now please.
Hoochie [10]

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never [62]

Answer:

The answers are given below.

Step-by-step explanation:

The computation is shown below:

1.a.

Profit Margin = Net Income ÷ Sales × 100

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1-b:

Average Assets = (Beginning Assets + Ending Assets) ÷ 2

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4 0
3 years ago
I need explanations. I don't understand this. Please click on the picture.
AlekseyPX
1. find the area of the two triangles, including the shaded section. the formula for this is a=1/2bh

the height and base are both 24 inches. this is because you add the 10 from the side of the square to the 14 that is given

so:

a=1/2(24)(24)
a=(12)(24)
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since there are two triangles, you would multiply the area by 2

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now, since you only need the unshaded section, you have to take away the shaded section, which is a square. to do this, you must calculate the area of the square and take it away from the area of both triangles.

a=576-(lw)
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that is your answer
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Lee can type 1 1/3 pages every 15 minutes. How many hours does it take him to type 10 2/3 pages
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Answer:

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