Answer:
y=-3x+20
Step-by-step explanation:
3/4x+1/4y=5
-3/4x -3/4x
1/4y=5-3/4x
divide the whole entire equation by 1/4 like this: (4)1/4y=4(5-3/4x)
Your answer is y=-3x+20
Well this is a quadratic equation so.
First we rearrange it
2y^2-2y-24
2y^2-2y-48
2y^2-8y+6y-24
2y(y-4)+6(y-4)
(2y+6)(y-4)
First let us calculate for the z score using the formula:
z = (x – u) / s
where x = 8, u is the mean = 12.7 years, s is the
standard deviation
z = (8 – 12.7) / 2.5
z = -1.88
From the standard probability tables, the p value at z =
-1.88 is:
P = 0.0301 = 3.01%
Answer:
![f(x)=x^2+16](https://tex.z-dn.net/?f=f%28x%29%3Dx%5E2%2B16)
Step-by-step explanation:
By the conjugate rule, if -4i is a root, then so is +4i. So we have 2 roots, thus, we have a second degree polynomial (namely, a quadratic). If
x = -4i, then
x + 4i is a root.
If
x = 4i, then
x - 4i is a root.
Having (x - 4i)(x + 4i) as roots, we can now FOIL them together to get a polynomial of least degree.
FOILing gives us
![x^2+4ix-4ix-16i^2](https://tex.z-dn.net/?f=x%5E2%2B4ix-4ix-16i%5E2)
Notice that the +4ix and the -4ix cancel each other out, leaving you with
![x^2-16i^2](https://tex.z-dn.net/?f=x%5E2-16i%5E2)
Since
![i^2=-1](https://tex.z-dn.net/?f=i%5E2%3D-1)
we can make the substitution:
![x^2-16(-1)](https://tex.z-dn.net/?f=x%5E2-16%28-1%29)
which simplifies to
![x^2+16](https://tex.z-dn.net/?f=x%5E2%2B16)
In function notation form:
![f(x)=x^2+16](https://tex.z-dn.net/?f=f%28x%29%3Dx%5E2%2B16)