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Ainat [17]
3 years ago
6

(12,-9) and (-2,-2) in slope intercept form and if u want the points please explain how u got it

Mathematics
1 answer:
Montano1993 [528]3 years ago
5 0

Answer:

y= -\frac{1}{2} x-3

Step-by-step explanation:

Slope intercept form :

y = mx + b

m is the slope

b is the y-intercept

Let's look for m, use the formula \frac{(y_{1}-y_{2} ) }{(x_{1} -x_{2} )} to determine it.

\frac{-9 - (-2)}{12 - (-2)} = -\frac{1}{2}

y = -\frac{1}{2}x+b

Now find b, we simply need to plug in one of our coordinates to get our answer.

(12, -9)

-9=-\frac{1}{2} (12)+b

Solve for b :

-9 = -6 + b

-3 = b

b = -3

Our slope intercept is :

y = -\frac{1}{2}x - 3

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Step-by-step explanation:

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5 0
2 years ago
Solve the equation and check the solution4.4x-4=3.4x
PolarNik [594]
4.4x-4=3.4x

Substract '-3.4x' at LHS nad the RHS of the above expression.

\begin{gathered} 4.4x-4-3.4x=3.4x-3.4x \\ 4.4x-3.4x-4=0 \\ x-4=0 \end{gathered}

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4 0
1 year ago
Mathematics question help
Nat2105 [25]

Distance Formula: \sqrt{(x_{2} - x_{1})^2 + (y_{2} - y_{1})^2}

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Point 2: (5,-8)

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4 0
3 years ago
Read 2 more answers
Choose the numbers that are terminating decimals. Select all that apply.
horsena [70]

Answer: A, C, and D

Step-by-step explanation:

          A terminating decimal is a decimal that has an end. In other words, \frac{1}{4}  =0.25 is one, but \frac{1}{3} =0.3333... is not.

✓ A. 0.032

✗ B. 0.999...

✓ C. 0.525

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3 0
2 years ago
If f(x) = 9x10 tan−1x, find f '(x).
djverab [1.8K]

Answer:

\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}

General Formulas and Concepts:

<u>Calculus</u>

Differentiation

  • Derivatives
  • Derivative Notation

Derivative Property [Multiplied Constant]:                                                           \displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)  

Basic Power Rule:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Derivative Rule [Product Rule]:                                                                             \displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle f(x) = 9x^{10} \tan^{-1}(x)

<u>Step 2: Differentiate</u>

  1. [Function] Derivative Rule [Product Rule]:                                                   \displaystyle f'(x) = \frac{d}{dx}[9x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]
  2. Rewrite [Derivative Property - Multiplied Constant]:                                  \displaystyle f'(x) = 9 \frac{d}{dx}[x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]
  3. Basic Power Rule:                                                                                         \displaystyle f'(x) = 90x^9 \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]
  4. Arctrig Derivative:                                                                                         \displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

7 0
3 years ago
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