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djyliett [7]
3 years ago
11

Can someone help solve?

Mathematics
2 answers:
icang [17]3 years ago
4 0

Answer:

scaning beep no data is acquired

hoa [83]3 years ago
4 0
The slope will be -2/5
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A market research firm used a sample of individuals to rate the purchase potential of a particular product before and after the
juin [17]

Answer:

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the commercial improved the mean purchase potential rating.

Step-by-step explanation:

If we calculate the difference in ratings we have:

After Before Difference

1 6 -5

5 2 3

6 4 2

3 7 -4

7 4 3

4 3 1

5 3 2

5 6 -1

9 8 1

7 7 0

5 8 -3

6 6 0

We will calculate the mean and standard deviation of the difference to test them later.

The sample size is n=12.

The mean is:

M=\dfrac{1}{12}\sum_{i=1}^{12}((-5)+3+2+(-4)+3+1+2+(-1)+1+0+(-3)+0)\\\\\\ M=\dfrac{-1}{12}=-0.083

The standard deviation is:

s=\sqrt{\dfrac{1}{(n-1)}\sum_{i=1}^{12}(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{11}\cdot [(-5-(-0.083))^2+(3-(-0.083))^2+...+(0-(-0.083))^2]}\\\\\\

s=\sqrt{\dfrac{1}{11}\cdot [(24.17)+(9.51)+...+(1.17)+(0.01)+(8.51)+(0.01)]}\\\\\\s=\sqrt{\dfrac{78.92}{11}}=\sqrt{7.174}\\\\\\s=2.678

The null hypothesis states that the mean rating "after" would be less than or equal to the mean rating "before." The alternative hypothesis states that the mean rating difference is greater than 0.

Then, the null and alternative hypothesis:

H_0: \mu\leq0\\\\H_a:\mu> 0

The significance level is 0.05.

The sample has a size n=12.

The sample difference is d=-0.083.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=2.678.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{2.678}{\sqrt{12}}=0.773

Then, we can calculate the t-statistic as:

t=\dfrac{\bar d}{s/\sqrt{n}}=\dfrac{-0.083}{0.773}=-0.108

The degrees of freedom for this sample size are:

df=n-1=12-1=11

This test is a right-tailed test, with 11 degrees of freedom and t=-0.108, so the P-value for this test is calculated as (using a t-table):

P-value=P(t>-0.108)=0.542

As the P-value is greater than the significance level, the effect is not significant. The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the commercial improved the mean purchase potential rating.

5 0
3 years ago
Susan is buying three different colors of tiles for her kitchen floor. She is buying 25 more red tiles than beige tiles, and thr
Setler [38]
Answer: 185-red tiles
               185-beige tiles
               75-navy blue tiles
6 0
3 years ago
Someone please help me with this
VikaD [51]

Answer:

c

Step-by-step explanation:

please see attached with explanation

hope it helps

4 0
3 years ago
Z=11+3(x+y)<br> Solve for x
Dafna11 [192]
Z=11+3(x+y) \\ Z=11+3x+3y \\ 3x=Z-11-3y \\ x= \frac{Z-11}{3} -y
6 0
4 years ago
Simplify 7-(x^2-3x+2)-2x(3x^2-x+1)
NeTakaya

Answer:

-6x^3+x^2+x+5

Step-by-step explanation:

distribute (multiply) the 7- into the first set of parenthesis. then distribute (multiply) the -2x into the second set of parenthesis.

3 0
3 years ago
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