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andrezito [222]
2 years ago
15

(1) Solve this system using the substitution method: y = x – 1; 4x – 3y = 6

Mathematics
1 answer:
ValentinkaMS [17]2 years ago
3 0

Answer:

(1)x=3, y=2

(2)x=19, y=31

Step-by-step explanation:

(1)

4x-3(x-1)=6

4x-3x+3=6

x+3=6

x=3

(2)

.76x+3.68y=128.52

x+y=50

.76x+3.68(50-x)=128.52

.76x+184-3.68x=128.52

.76x-3.68=-55.48

-2.92x=-55.48

x=19

19+y=50

y=31

This took so much work....  I hope I helped you well.

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(3, 5)

Step-by-step explanation:

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Underage drinking, Part I: Data collected by the Substance Abuse and Mental Health Services Administration (SAMSHA) suggests tha
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Answer:

a. <u>Yes, there are 10 independent trials, each with exactly two possible outcomes, and a constant probability associated with each possible outcome.</u>

b. <u>The probability is 0.2029 or 20.29%</u>

c. <u>The probability is 0.2029 or 20.29%</u>

d. <u>The probability is 0.1671 or 16.71%</u>

e. <u>The probability is 0.9975 or 99.75%</u>

Step-by-step explanation:

<u>a. Yes, there are 10 independent trials, each with exactly two possible outcomes, and a constant probability associated with each possible outcome.</u>

b. Let's use the binomial distribution table, this way:

Binomial distribution (n=10, p=0.697)

 f(x) F(x) 1 - F(x)

x Pr[X = x] Pr[X ≤ x]

0 0.0000 0.0000

1 0.0002 0.0002

2 0.0016 0.0017

3 0.0095 0.0112

4 0.0384 0.0496

5 0.1059 0.1555

6 <u>0.2029</u> 0.3584

7 0.2668 0.6252

8 0.2301 0.8553

9 0.1176 0.9729

10 0.0271 1.0000

<u>The probability is 0.2029 or 20.29%</u>

c. If 69.7% of 18-20 years old consumed alcoholic beverages in 2008, therefore, 30.3% did not and the binomial distribution table is:

Binomial distribution (n=10, p=0.303)

 f(x) F(x) 1 - F(x)

x Pr[X = x] Pr[X ≤ x]

0 0.0271 0.0271

1 0.1176 0.1447

2 0.2301 0.3748

3 0.2668 0.6416

4 <u>0.2029</u> 0.8445

5 0.1059 0.9504

6 0.0384 0.9888

7 0.0095 0.9983

8 0.0016 0.9998

9 0.0002 1.0000

10 0.0000 1.0000

<u>The probability is 0.2029 or 20.29%</u>

d. Let's use the binomial distribution table, this way:

Binomial distribution (n=5, p=0.697)

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x Pr[X = x] Pr[X ≤ x]

0 0.0026 0.0026

1 0.0294 0.0319

2 0.1351 <u>0.1671 </u>

3 0.3109 0.4779

4 0.3576 0.8355

5 0.1645 1.0000

P(0) + P(1) + P (2) = 0.0026 + 0.0294 + 0.1351

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P(1) + P (2) + P(3) + P(4) + P (5) = 0.0294 + 0.1351 + 0.3109 + 0.3576 + 0.1645

<u>The probability is 0.9975 or 99.75%</u>

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