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IceJOKER [234]
2 years ago
6

1 4 cm 4 cm 5 cm 3 cm Perimeter: Area:​

Mathematics
1 answer:
ohaa [14]2 years ago
7 0

Answer:

Step-by-step explanation:

840

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How many sales would you make a week? i would make between 3 and 5 sales per week?
svp [43]
You will make 4 sales if you are making a sale between 3 and five because 4 is whats in between 3 and 5. If your are to compute you will make a sale of average 4 because the average of 3 and 4 is 5. Computed as 3+5/2=4.
7 0
2 years ago
What equation describes the circle that is centered at (8, 3) and has a radius of 9
Sloan [31]

Answer:

<h3> (x-8)²+(y-3)² = 81</h3>

Step-by-step explanation:

The general equation of a circle is expressed as;

(x-a)²+(y-b)² = r² where;

(a, b) is the centre of the circle

r is the radius

Given the centre (8, 3) and the radius of 9, the equation of the circle will be;

(x-a)²+(y-b)² = r²

(x-8)²+(y-3)² = 9²

(x-8)²+(y-3)² = 81

hence the required equation is  (x-8)²+(y-3)² = 81

5 0
2 years ago
Find the area bounded by the graphs of the indicated equations over the given interval.
NeX [460]

Answer:

48

Step-by-step explanation:

y = 0

is basically the horizontal axis.

First, find the integral of x^2-25.

Remember that

integral of a constant is that constant times x.

Also that

to take the integral of a power function, add 1 to the degree and divide by that same degree.

y =  {x}^{2}  - 25

We then get

\frac{ {x}^{3} }{3}  - 25x

Evaluate at -3

\frac{ - 3 {}^{3} }{3}  - 25( - 3)

- 27 + 75 = 48

Then we evaluate at 0

\frac{0 {}^{3} }{3}  - 25(0) = 0

Next, we subtract the the answer then we get

48 - 0 = 48

8 0
2 years ago
Five less than the product of 7 and a number is equal to 3.
mr Goodwill [35]

Answer:

x = 8/7

Step-by-step explanation:

Step 1: Convert to math

7x - 5 = 3

Step 2: Solve for <em>x</em>

  1. Add to both sides: 7x = 8
  2. Divide both sides by 7: x = 8/7
6 0
2 years ago
Solve the inequality. 42 &lt; –6d
____ [38]
Divide both sides by -6 and don't forget to flip the inequality symbol
-7>d
d<-7
4 0
3 years ago
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