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The general equation of a circle is x^2 + y^2 = r^2. Here we know that the circle passes thru two points: (-3,2) and (1,5). Given that a third point on the circle is (-7, ? ), find the y-coordinate of this third point.
Subst. the known values (of the first point) into this equation: (-3)^2 + (2)^2 = r^2. Then 9 + 4 = 13 = r^2.
Let's check this. Assuming that the equation of this specific circle is
x^2 + y^2 = r^2 = 13, the point (1,5) must satisfy it.
(1)^2 + (5)^2 = 13 is not true, unfortunately.
(1)^2 + (5)^2 = 1 + 25 = 26 (very different from 13).
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Answer:
Option D. {–7, 7}
Step-by-step explanation:
3n^2 = 147
First, divide both side 3
n^2 = 147/3
n^2 = 49
Next, rearrange the variables to one side of the equation as shown below:
n^2 — 49 = 0
n^2 — 7^2 = 0
The above is now difference of two squares. This can be solve by doing the following:
(n — 7)(n + 7) = 0
n — 7 = 0 or n + 7 = 0
n = 7 or n = —7
Answer:
a. 5.26
Step-by-step explanation:
As, the standard deviation of the distribution of the difference between mean is 0.76 so the t score will be simply calculated by dividing the difference of means by standard deviation of the distribution of the difference between mean as hypothesized difference is zero.
t score=Xbar A- Xbar B/Sd of difference of means
t score=55-51/0.76
t score=4/0.76=5.26
Use PENDAS it helps a lot.
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