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3 years ago

Select all that apply. To create perpendicular lines, I can transform a line by:

Mathematics

1 answer:

IceJOKER [234]3 years ago

5 0

Answer:

8. Rotating the line 90° around any point.

Step-by-step explanation:

Perpendicular lines intersect each other at a right angle. Therefore, the transformation should create an image that intersects the preimage at an angle of 90∘. Since a rotation changes the angle between the preimage and the image, it can create perpendicular lines.

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AB and BC are perpendicular lines find the value of x.

Bess [88]

Answer:

X=42

Step-by-step explanation:

AB and BC make a right angle

So, 24°+x+24° =90°

48°+x=90°

X=90°-48°

X=42

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3 years ago

Read 2 more answers

8x - 12 = 20 what is x?

PSYCHO15rus [73]

Answer:

Step-by-step explanation:

add 12 to 20 then divide 32 by 8

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4 years ago

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3241004551 [841]

Answer:

SSS similarity

Step-by-step explanation:

From the smaller triangle to the larger triangle, the ratio of each pair of corresponding sides is 2.

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2 years ago

LaTonda rolls two number cubes that are each numbered 1 through 6. What is the probability that the sum of the numbers on the to

ZanzabumX [31]

Answer:

1/4

Step-by-step explanation:

The maximum sum of the two cubes is 6 + 6 = 12

The multiples of 4 until 12 are: 4, 8 and 12.

each cube has 6 possible values, so two cubes have a total of 6 * 6 = 36 possible results

We can have a sum of 4 with the pairs (1,3), (2,2), (3,1).

We can have a sum of 8 with the pairs (2,6), (3,5), (4,4), (5,3), (6,2)

We can have a sum of 12 with the pair (6,6)

So we have a total of 9 pairs that satisfy our condition over a total of 36 possibilities, so the probability is 9 / 36 = 1/4

8 0

3 years ago

Integrate dx/3sinx+4cosx

german

$\displaystyle\int\frac{\mathrm dx}{3\sin x+4\cos x}$

A standard approach would be the tangent half-angle substitution:

$t=\tan\dfrac x2\implies\mathrm dt=\dfrac12\sec^2\dfrac x2\,\mathrm dx$

Then

$\sin x=2\sin\dfrac x2\cos\dfrac x2\implies\sin x=\dfrac{2t}{1+t^2}$

$\cos x=\cos^2\dfrac x2-\sin^2\dfrac x2\implies\cos x=\dfrac{1-t^2}{1+t^2}$

from which we get

$\mathrm dx=\dfrac2{1+t^2}\,\mathrm dt$

So the integral becomes

$\displaystyle\int\frac{\frac2{1+t^2}}{\frac{6t}{1+t^2}+\frac{4(1-t^2)}{1+t^2}}\,\mathrm dt=\int\frac{\mathrm dt}{3t+2(1-t^2)}=-\int\frac{\mathrm dt}{2t^2-3t-2}$