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11Alexandr11 [23.1K]
2 years ago
10

Need help asap!!!!!!!!!!

Mathematics
1 answer:
boyakko [2]2 years ago
7 0

Answer:

Triangles ABC and DCB are congruent by SAS

Step-by-step explanation:

Angle CAB is congruent to angle CDB. Side DB is congruent to side AC. Then Ab is congruent to side CD.

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Plzz help me im giving 12 points
Serggg [28]
This Is very simple.

30m + 50 = 20m + 100

This is the new equation needed to solve for m.
first we must isolate "m".

30m + 50 = 20m + 100
        - 50             - 50

30m = 20m + 50
-20m   -20m

10m = 50

divide both sides by 10 to isolate "m".

m = 5

hope this helps!





3 0
3 years ago
Type the expression that results from the following series of steps:
d1i1m1o1n [39]

Answer:

(x-6)3

hope it helps

4 0
3 years ago
Read 2 more answers
Line AB contains points A(-6,3) and B(2,-5). Line AB has a slope that is?
dexar [7]
I believe its -1 because x2-x1/y2-y1 good luck
7 0
3 years ago
Land in downtown Columbia is valued at $10 a square foot. What is the value of a triangular lot with sides of lengths 119, 147,
stiks02 [169]

Answer:

$87,461

Step-by-step explanation:

Given that the dimensions or sides of lengths of the triangle are 119, 147, and 190 ft

where S is the semi perimeter of the triangle, that is, s = (a + b + c)/2.

S = (119 + 147 + 190) / 2 = 456/ 2 = 228

Using Heron's formula which gives the area in terms of the three sides of the triangle

= √s(s – a)(s – b)(s – c)

Therefore we have = √228 (228 - 119)(228 - 147)(228 - 190)

=> √228 (109)(81)(38)

= √228(335502)

=√76494456

= 8746.1109071 * $10

= 87461.109071

≈$87,461

Hence, the value of a triangular lot with sides of lengths 119, 147, and 190 ft is $87,461.

6 0
3 years ago
Please help me with number 11
photoshop1234 [79]

Answer:

it is twice as long(10/12 inches longer

Step-by-step explanation:

1 4/6 make the 6 a 12 and the four a 8. 1= 12/12 so 8+12=20 so 20/12 and 20 is 10/12 more that 10/12 or twice as much.

8 0
3 years ago
Read 2 more answers
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